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Scilla [17]
3 years ago
9

Just help me please

Mathematics
2 answers:
scoray [572]3 years ago
8 0
Just download photo math, it’s super easy and the answers are always right

nikitadnepr [17]3 years ago
3 0

\left( \dfrac{4}{5} \right)^{-3}

There are a few ways to approach this.  

My preference is to apply that -3 exponent to both the top and the bottom:

    \left( \dfrac{4}{5} \right)^{-3} = \dfrac{4^{-3}}{5^{-3}}

I'd do that the same way, no matter whether the exponent outside was a postive or negative number.

Since it is a negative number, I remember that negative exponents mean that factor is on the wrong side of the fraction.  So anything with a negative exponent will move to the other side.  

    \dfrac{4^{-3}}{5^{-3}} = \dfrac{5^3}{4^3}

Be sure to make the exponents' signs change when you move them to the other side of the fraction.

Finally I would evaluate 5^3 and 4^3 on their own to get my answer.

    \dfrac{5^3}{4^3} = \dfrac{5 \cdot 5 \cdot 5}{4\cdot 4 \cdot 4} = \dfrac{~~~?~~~}{?}

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