The correct answer is B. The parents are heterozygous with polka-dot tails, so they both have Pp genotype. The combination of their genotypes (Pp x Pp) could produce 4 genotypes PP, Pp, Pp and pp. Therefore, there is 25% chance for a PP genotype, 25% for a pp genotype and 50% for a Pp genotype. The PP and Pp genotypes produce a polka-dot tail phenotype and the pp genotype produces a solid coloured tail phenotype. In conclusion, there is 75% chance for a polka-dot tail (25% for a PP + 50% for a Pp) and a 25% for a solid coloured tail phenotype (25% for a pp).
Answer:
If there are no plants in the tank, they will run out of oxygen because there is nothing producing oxygen.
Explanation:
The resulting mice will be induced with the changed gene either on or off. The offspring will have altered genes if both the alleles have the trait. This is a heritable change.
Explanation:
Making gene on or off is a process of gene regulation when one of the gene is methylated or histone modification to prevent access to transcription factors hence no expression of the protein. This process is called epigenetics.
The resulting progeny in mice will receive the allele of on or off the gene. Such genes with altered allele are also called as
The altered genes will be expressed in the resulting progeny of mice.
The epigenetic genes can be reverted with environmental effects in the offspring paramutable alleles. They are heritable.
Answer: Scientific name: Felis catus.
Explanation: I hope this helps :p
Answer:
Scientists believe that prokaryotes existed earlier than eukaryotes because certain eukaryote cell structures resemble prokaryotes.
Explanation:
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