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3 years ago

3/9 - 2??????????????????

Mathematics

1 answer:

natima [27]3 years ago

5 0

The answer will be to this equation is 0.1

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Consider the graph of function f. Find the average rate of change for f on the interval [P,Q]

Ulleksa [173]

Check the picture below.

$\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{31em}{0.25pt}\\\\ f(x)= \qquad \begin{cases} x_1=1\\ x_2=3 \end{cases}\implies \cfrac{f(3)-f(1)}{3-1}\implies \cfrac{(5)-(-1)}{3-1} \\\\\\ \cfrac{5+1}{2}\implies \cfrac{6}{2}\implies 3$

4 0

3 years ago

Help complete the table for the equation y= x - 2. Then use the table to graph the equation.

Goryan [66]

Answer:

-4, -3, -2, -1, 0

Step-by-step explanation:

Using the equation y = x -2, substitute the values for x into the equation and solve for y.

y = -2 -2

y = -4

y = -1 - 2

y= -3

y = 0 - 2

y = -2

y = 1 - 2

y = -1

y = 2 - 2

y = 0

You will have the coordinates when you plug the numbers into the table. (-2, -4), (-1, -3), (0, -2), (1, -1), (2, 0). Plot the points and connect with a line.

3 0

2 years ago

Mrs. Cooper has 51.2 pounds of soil. She uses 12.9 pounds of soil for her houseplants and 30.4 pounds of soil for her garden How

myrzilka [38]

Answer:

7.9

Step-by-step explanation:

She has a total of 51.2 and uses 12.9+30.4.

The equation would be 51.2-(12.9+30.4).

51.2-(12.9+30.4)

=51.2-43.3

=7.9

Have a nice day!!!!!!! :-)

3 0

3 years ago

The rule is y=− 3/4 x+ 1 /4

Effectus [21]

The answer is C because y=-3/4 which is a negative.

7 0

3 years ago

Find an exact value cos(19pi/12)

dmitriy555 [2]

$cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}$

Step-by-step explanation:

We know that

cos 2x = 2cos²x - 1

So we have

$cosx=\sqrt{\frac{1+cos2x}{2}}$

Substituting $x=\frac{19\pi}{12}$

$cos\left ( \frac{19\pi}{12}\right )=\sqrt{\frac{1+cos2\left ( \frac{19\pi}{12}\right )}{2}}\\\\cos\left ( \frac{19\pi}{12}\right )=\sqrt{\frac{1+cos\left ( \frac{19\pi}{6}\right )}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{1+cos570}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{2-\sqrt{3}}{4}}\\\\cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}$

$cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}$

3 0

3 years ago

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