Answer: (a) 0.317
(b) 0.167
(c) Not unusual
Step-by-step explanation:
Probability is defined as the chance of an event occurring.
Let S be a sample space and A be an event in the sample space, the probability of event A occurring can be found using the following:
P(A) = n(A) divided by n(S) where n(A) = number of elements in event A and n(S) = number of elements in the sample space.
(a) P(Right field) = Number of hits to the right field divided by total number of hits
= 1919/6060
= 19/60 which is approximately equal to 0.317
(b) P(Left field) = 1010/6060
= 1/6 which is approximately equal to 0.167
(c) The probability that the home run was hit to the left field is 0.167.
The probability of an unusual event is 0, therefore, it is possibly for the
player to hit a home run to the left.
Answer:
a)e^-(λ20891)
b)1-e^-(λ30598)
c)1-e^-(λ30598)-e^-(λ20891)
Step-by-step explanation:
The probability density function (pdf) of an exponential distribution is
f(x,λ)=λe^-(λx) for x>0, and 0 for x<0
The cumulative distribution function is given by
F(x,λ)=1-e^-(λx) for x>0, and 0 for x<0
P(X≥20891)=1-P(X≤20891)=1-F(20891,λ)=e^-(λ20891)
P(X≤30598)=F(30598,λ)=1-e^-(λ30598)
P(20891≤X≤30598)=F(30598,λ)-(20891,λ)=1-e^-(λ30598)-e^-(λ20891)
Answer:
h≈25.47
Step-by-step explanation:
h=V/πr2
you just plug in the radius and volume into the equation
Answer to part A: 11w^2+7z^2
Answer to part B: 14w^2+9w
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Explanation:
For part A, the expression 4w^2+7w^2+7z^2 has one pair of like terms. That pair is 4w^2 and 7w^2 which combine to 11w^2. You add the coefficients to get 4+7 = 11, then tack w^2 onto everything to say 4w^2+7w^2 = 11w^2
We cannot combine 11w^2 and 7z^2 as they aren't like terms. So we leave it as 11w^2+7z^2
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In part B, the like terms are 15w and -9w. They combine to 15w-9w = 6w. You can think of it like 15-9 = 6 then stick a 'w' to each term. We cannot combine the w^2 term with the w terms.
