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saveliy_v [14]
4 years ago
15

An experiment consists of tossing a coin and drawing a card, with the card-drawing stage dependent on the result of the coin tos

s. If heads occurs, then a card is selected at random from the clubs and spades suits. If tails occurs, then a card is selected at random from the hearts and diamonds suits. What is the size of the sample space of this two-stage experiment?
Mathematics
1 answer:
Rom4ik [11]4 years ago
4 0

In every side of the coin, there is a fifty fifty chance of landing on the other side, so there is a probability of 0.50. In a deck of cards, there are 52 cards with 26 clubs and another 26 for spades. So in every random choice, there is a 1/26 probability of the card being chosen.

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No Solutions<br> 5x - 2x + 7 - x = _x + _
Eddi Din [679]

Answer:

2x+7

Step-by-step explanation:

To Simplify an Expression , we combine Like-Terms

So for our Question , we have Terms with x and Constant Term

Combine Terms with x : 5x-2x-x=2x

Constant Term : 7

Then 5x-2x+7-x = 2x+7

5 0
2 years ago
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Write a polynomial in standard form with the zeros -4,0, 1, and 4.
gavmur [86]

Answer: x^4-x^3-16x^2+16x

Step-by-step explanation:

Factor theorem : If x=a is a zero of a polynomial p(x) then (x-a) is a factor of p(x).

Given: Zeroes of polynomial : -4,0, 1, and 4.

Then Factors = (x-(-4)), (x-0), (x-1) and (x-4)   [By factor theorem ]

=(x+4), (x-0), (x-1) and (x-4)

Multiplying these factors to get polynomial in standard form.

(x+4)\times(x-0)\times(x-1)\times(x-4)  \\\\= x(x+4)(x-4)(x-1)\\\\= x(x^2-4^2)(x-1)\\\\= x(x^2-16)(x-1)\\\\= x(x^2-16)(x-1)\\\\=x(x^2x+x^2\left(-1\right)+\left(-16\right)x+\left(-16\right)\left(-1\right))\\\\= x(x^3-x^2-16x+16)\\\\=x^4-x^3-16x^2+16x

Hence, B is the correct option.

8 0
3 years ago
On the box and whisker plot below, what data calculations do the points B and D represent?
daser333 [38]

Answer:

Lower and upper quartiles

Step-by-step explanation:

The box starts at lower quartile, ends at upper quartile

5 0
4 years ago
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ddd [48]
The first mechanic would get $75 per hour and <span>the second mechanic would get $55 per hour</span>
4 0
3 years ago
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An English teacher has 6 short stories, 4 novels, and 23 poems to choose from. How many ways can he assign one of each to his cl
Karolina [17]

Answer:

552

Step-by-step explanation:

This is a problem of permutation which can be solved by rule of fundamental counting principle.

This principle states that if there "m" ways of doing one thing and "n" ways of doing other. Then no. of ways in which both the things can be done together is "m*n". This can be extended for m, n, p,r, s things and so on.

example: if there are 5 shirts and 3 trousers then number of ways in which the shirts and trousers can be worn is 5*3 = 15 ways.

_____________________________________________

The given problem is on similar concepts.

here  6 short stories, 4 novels, and 23 poems have to be assigned to his class.

Thus it can be done in 6*4*23 = 552 ways.

5 0
3 years ago
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