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ad-work [718]
3 years ago
5

70+ 5x < 30+15x I know that x =5 But can someone help me with a real world problem ?

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0
Remember, you can do anything to an equation as long as you do it to both sides
but, for inequalities, if you multiply or divide both sides by a negative, you flip the sign


70+5x<30+15x
minus 5x both sides
70<30+10x
minus 30 both sides
40<10x
divide both sides by 10
4<x

x>4 is the solution set

a real world problem could be


company A charges a flat rate of $70 dollars to rent their car and also charge a rate of $5 per mile driven

company B charges a flat rate of $30 dollars to rent the car and also charge $15 per mile

how many miles do you have to drive for you to pay more for company B than A?
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Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

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Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

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Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

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Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

Step 2: Cancel 14©(7 on the right side: 0o = 0 Step 3: Divide each side of the equation by 0

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