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3 years ago

6

Daniel is making a cube using blocks. The cube is solid and has no holes.

2 answers:

astraxan [27]3 years ago

6 0

D because if you look at 81x9 it will get you too 729

cestrela7 [59]3 years ago

4 0

Its d 729 because on 1 layer theres are 81 cubes and there are 9 layers so 81 times 9 equals 729

Hope this helps

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2 years ago

The test scores on a 100-point test were recorded for 20 students:71 93 91 86 7573 86 82 76 5784 89 67 62 7277 68 65 75 84a. Can

Dafna11 [192]

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b. mean = 76.65

standard deviation = 10.04

c. 76.65 ± 4.4

Step-by-step explanation:

a. <u>Stem</u> <u>and</u> <u>leaf</u> <u>Plot</u> shows the frequencies with which classes of value occur. To create this plot, we divide the set of numbers into 2 columns: <u>stem</u>, the left column, which contains the tens digits; <u>leaf</u>, the right column, which contains the unit digits.

<u>Normal</u> <u>distribution</u> is a type of distribution: it's a bell-shaped, symmetrical, unimodal distribution.

A stem and leaf plot displays the main features of the distribution. If turned on its side, we can see the shape of the data.

The figure below shows the stem and leaf plot of the 100-point test score. As we can see, when turned, the plot resembles bell-shaped distribution. So, this test scores were selected from a normal population.

b. <u>Mean</u> is the average number of a data set. It is calculated as the sum of all the data divided by the quantity the sample has:

mean = $\frac{\Sigma x}{n}$

For the 100-point test score:

mean = $\frac{71+93+91+...+65+75+84}{20}$

mean = 76.65

<u>Standard</u> <u>Deviation</u> determines how much the data is dispersed from the mean. It is calculated as:

$s=\sqrt{\frac{\Sigma (x-mean)^{2}}{n-1} }$

For the 100-point test score:

$s=\sqrt{\frac{[(71-76.65)+(93-76.65)+...+(84-76.65)]^{2}}{20-1} }$

s = 10.04

The mean and standard deviation of the scores are 76.65 and 10.04, respectively.

c. <u>Confidence</u> <u>Interval</u> is a range of values we are confident the real mean lies.

The calculations for the confidence interval is

mean ± $z\frac{s}{\sqrt{n} }$

where

z is the z-score for the 95% confidence interval, which is equal 1.96

Calculating interval

76.65 ± $1.96.\frac{10.04}{\sqrt{20} }$

76.65 ± 4.4

The 95% confidence interval for the average test score in the population of students is between 72.25 and 81.05.

7 0

3 years ago