Answer:
Cost of a coffee is <u>$2.5</u> and cost of a latte is <u>$4.25.</u>
Step-by-step explanation:
Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.
Given:
4 coffees and 12 lattes cost $61.
12 coffees and 7 lattes cost $59.75.
∵ 1 coffee cost =
∴ 4 coffees cost = and 12 coffee cost =
∵ 1 latte cost =
∴ 12 lattes cost = and 7 lattes cost =
Now, as per question:
Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,
Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,
Therefore, cost of a coffee is $2.5 and cost of a latte is $4.25.
Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing
Answer:
60$
Step-by-step explanation:
Shipping is 7.50 and the 7 items are 52.5 total
The factors for given equation f(x)=.
- (x-1) - No
- (x-3) - No
- (x+3) - Yes
- (x-5) - Yes
- (x+5) - Yes
<u>Step-by-step explanation:</u>
The given equation is f(x)= .
Add 0 at the end of the equation.
= 0.
Let us group the given equation,
=0.
⇒ Group 1: .
Group 2: .
Pull out factor from each group,
⇒ Group 1: .
Group 2: (x+3) (-25).
Join the two group since both (x+3) is common in both groups.
=0.
One of the factor is (x+3).
Other factors are solved by the formula, .
= (x+5) (x-5) .
The other factors are (x+5) and (x-5).
Answer:
1,518,000 committees.
Step-by-step explanation:
We have been given that the judiciary committee at a college is made up of three faculty members and four students. Ten faculty members and 25 students have been nominated for the committee.
We will use combinations for solve our given problem.
, where,
n = Number of total items,
r = Items being chosen at a time.
Therefore, 1,518,000 judiciary committees could be formed at this point.