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3 years ago

The cube of the difference of 4 times x and 9

Mathematics

1 answer:

grigory [225]3 years ago

8 0

Answer:

Step-by-step explanation:

Write the statement into an expression

<h2>(4x - 9)³</h2><h2 /><h3>Now multiply that out...</h3><h3 /><h3>(4x - 9)²(4x - 9)</h3><h3 /><h3> Foil the first binomial</h3><h3 /><h3> (16x² - 72x + 81)(4x - 9)</h3><h3 /><h3>Multiply the two polynomials together</h3><h3 /><h3> 16x²(4x) - 72x(4x) + 81(4x) + 16x²(-9) - 72x(-9) + 81(-9)</h3><h3 /><h3> 64x³ - 288x² + 324x - 144x² + 648x - 729</h3><h3 /><h3>combine like terms...</h3><h3 /><h3>64x³ - 432x² + 972x - 729</h3>

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Collins is working.......

lesya [120]

Let n represent the amount Colin earned on Sunday.

On Sat. he earned n/2; on Sun. he earned n; and on Friday he earned (1/2)(n/2).

Then n/2 + n + n/4 = $70

Mult. all terms by 4 to eliminate fractions:

2n + 4n + n = $280

7n = $280 => n = $40

Colin earned n/2, or $20, on Saturday; n, or $40, on Sunday; and n/4, or $10, on Friday.

Note that $20 and $40 and $10 add up to $70, as they must.

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3 years ago

Solve. 489.209 + 43.9

lidiya [134]

Answer:

533.109

Step-by-step explanation:

Just add all the numbers

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3 years ago

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IRINA_888 [86]

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3 years ago

HELPPPPP ME GUYSSSS........

tamaranim1 [39]

Answer:

$\rm\displaystyle (x + 2{)}^{2} + (y + 5 {)}^{2} = {1}^{}$

$\rm\displaystyle (x - 7{)}^{2} + (y + 3{)}^{2} = { 7 }$

Step-by-step explanation:

<h3>QUESTION-1:</h3>

we are given the center and the redious of a circle equation

remember that,

$\rm\displaystyle E _{c} :(x - h {)}^{2} + (y - k {)}^{2} = {r}^{2}$

where (h,k) is the centre coordinate and r is redious of the circle

given that, h=-2 , k=-5 and r=1

Thus substitute:

$\rm\displaystyle (x - ( - 2){)}^{2} + (y - ( - 5) {)}^{2} = {1}^{2}$

simplify:

$\rm\displaystyle (x + 2{)}^{2} + (y + 5 {)}^{2} = {1}^{}$

<h3>QUESTION-2:</h3>

Likewise

$\rm\displaystyle E _{c} :(x - h {)}^{2} + (y - k {)}^{2} = {r}^{2}$

given that,h=7,k=-3 and r=√7

substitute:

$\rm\displaystyle (x - (7{))}^{2} + (y - ( - 3){)}^{2} = { \sqrt{7} ^{2} }$

simplify:

$\rm\displaystyle (x - 7{)}^{2} + (y + 3{)}^{2} = { 7 }$

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3 years ago

A recursive function is shown below:

Ber [7]

$f(1)=\fbox2\ and\ f(n)=f(n-1)-5\\\underline{f(2)}=f(2-1)-5=f(1)-5=2-5=\fbox{-3}\\\underline{\underline{f(3)}}=f(3-1)-5=\underline{f(2)}-5=-3-5=\boxed{-8}\\f(4)=f(4-1)-5=\underline{\underline{f(3)}}-5=-8-5=\boxed{-13}\\\vdots\\Answer:\boxed{\boxed{2;-3;-8;-13;-18;...}\leftarrow answer}$

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3 years ago