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alexgriva [62]
3 years ago
5

A QUESTION ABOUT MATHS:

Mathematics
1 answer:
posledela3 years ago
3 0

Answer:

a, 7C5 = 21 ways

b, 11C5 = 462 ways

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Three numbers are in the ratio 6:3:1, and the sum of these numbers is 420. If the first number is reduced by 50%, and the second
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x:y:z\ \ \ \Leftrightarrow\ \ \ 6:3:1\\ \\ \frac{x}{z} =\frac{6}{1}\ \ \ \Rightarrow\ \ \ x=6z\ \ \ \ \ \ \ and\ \ \ \ \ \ \ \frac{y}{z} =\frac{3}{1}\ \ \ \Rightarrow\ \ \ y=3z\\ \\x+y+z=420\ \ \ \Rightarrow\ \ \ 6z+3z+z=420\ \ \ \ \Rightarrow\ \ \ \ 10z=420\ /:10\\ \\z=42\ \ \ \Rightarrow\ \ \ \ x=6\cdot42=252\ \ \ \ and\ \ \ \ y=3\cdot42=126\\ \\ \\a=x-50\%x=50\%x= \frac{1}{2} \cdot252=126=3\cdot42\\ \\b=y+42=126+42=168=4\cdot42\\ \\c=420-126-168=126=3\cdot42\\ \\a:b:c\ \ \ \Leftrightarrow\ \ \ 3:4:3
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Helppp!! Find the volume of the cone
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2 5/6, 2 6/8 1 7/12 is the way you would order it.
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Sorry wrote down the wrong thing the first time. Try doing 2 plus 3 times 5.

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