If sin Ф=1/3>0 and tan Ф<0; then Ф belongs to the second quadrant and cos Ф will be negative (cos Ф<0).
sin²Ф+cos²Ф=1
(1/3)²+cos²Ф=1
1/9+cos²Ф=1
cos²Ф=1-1/9
cos²Ф=8/9
cos Ф=⁺₋√(8/9)=⁺₋2√2 / 3
We have two possible solutions.
cos Ф=2√2 / 3 This solutions is not possible, because in this case cos Ф has to be negative (cos Ф<0)
cos Ф=(-2√2) / 3 this solutions is right.
answer:B. -2 square root 2 /3 (or (-2√2) /3 )
Answer:
-5.
Step-by-step explanation:
f(n) = 5n + 6
Just plug in -11/5 for n:
f(-11/5) = 5 (-11/5) + 6
= -11 + 6
= -5.
3 because 2*12 24 24/8 is 3 hope this helps
As, 
=0.301029+0.845098+1.13943
=2.26007
=2.260(approximate)
