At the start, the tank contains
(0.02 g/L) * (1000 L) = 20 g
of chlorine. Let <em>c</em> (<em>t</em> ) denote the amount of chlorine (in grams) in the tank at time <em>t </em>.
Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of
(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s
In case it's unclear why this is the case:
The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.
So the amount of chlorine in the tank changes according to
which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5<em>t</em> )^(5/3), then integrate both sides to solve for <em>c</em> (<em>t</em> ):
![\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5B%5Cdfrac%7Bc%28t%29%7D%7B%28200-3t%29%5E%7B5%2F3%7D%7D%5Cright%5D%3D0)
There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :
![\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}](https://tex.z-dn.net/?f=%5Cimplies%5Cboxed%7Bc%28t%29%3D%5Cdfrac1%7B200%7D%5Csqrt%5B3%5D%7B%5Cdfrac%7B%28200-3t%29%5E5%7D5%7D%7D)
This is what I put in my response
For me I thought that algebra was better. I loved algebra I mean math is math somethings in math are hard, somethings are easy, sometimes in math you will come across something that seems impossible. Sometimes you will fly thru but, what makes the journey bearable is the people around you. Why I think algebra is better is because of the people that were in math course with me and my teacher because. The teachers make all the difference.
We don’t know the number of employees remaining at the company.
We don’t know the total number of employees remaining at the company.
The classification consists of gender, division, and employment type.
It doesn’t matter what order those attributes come in. A person who is male, age group 6, and employment type 10 has the same classification as someone who is of employment type 6, male, and age group10.
Therefore since order does not matter it is a combination question.
Assuming only two genders are allowed (you didn’t say and some people think there are about 10 of them)
It is either 120 (2 times 6 times 10) or "None of the above" if you believe there are more than 2 genders.
2×6×10=120
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Answer: For plato family
A fossil with 47% of its carbon remaining is approximately how old
2998
A fossil that is 7000 years old will have approximately
17%
Step-by-step explanation:
Answer:
9cm
Explicación:
El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:
Donde c es la hipotenusa y a y b son los catetos.
Por lo cual, podemos reemplazar c por 15cm y a por 12cm :
Finalmente , debemos resolver la ecuación para b, así que b es igual a :
Por lo tanto, la longitud del otro cateto es 9 cm
