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2 years ago

-3(2x+2)<10 thank you in advance

1 answer:

6 0

$-3(2x+2) < 10\\\\\implies -6x -6 < 10\\\\\implies -6x < 10 +6\\\\\implies -6x < 16 \\\\\implies x > -\dfrac{16}6\\\\\implies x > -\dfrac{8}3$

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A number between 61-107 and are multiples of 3,8,12

Sergeu [11.5K]

72 is the answer you are looking for here

3 0

3 years ago

For the following hypothesis test, H0: μ ≥ 150Ha: μ < 150the test statistic a. must be positive. b. must be negative. c. can

Virty [35]

Answer:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

And since we are conducting a lower unilateral lest then we expected that the value for the statistic would be negative. And the correct answer would be:

b. must be negative

Step-by-step explanation:

Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =150$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean is lower than 150, the system of hypothesis would be:

Null hypothesis: $\mu \geq 150$

Alternative hypothesis: $\mu < 150$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

And since we are conducting a lower unilateral lest then we expected that the value for the statistic would be negative. And the correct answer would be:

b. must be negative

7 0

3 years ago

Find the 53rd term of the arithmetic sequence<br> 27,11, -5

vivado [14]

Answer:

The 53rd term of this arithmetic sequence is -805.

Step-by-step explanation:

The general rule of an arithmetic sequence is the following:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term, that is, $d = a_{3} - a_{2} = a_{2} - a_{1}$ .

To find the nth term of the sequence, this equation can be written as:

$a_{n} = a_{1} + (n-1)d$

27,11, -5

So $a_{1} = 27, a_{2} - a_{1} = 11 - 27 = -16[/tex[tex]a_{n} = a_{1} + (n-1)d$

$a_{53} = a_{1} + (52)d = 27 + 52*(-16) = -805$

The 53rd term of this arithmetic sequence is -805.

3 0

3 years ago

4) Use the distance formula to find the length of segment BC.

gogolik [260]

Answer:

Step-by-step explanation:

d= √(5-1)^2+(1-4)^2

d= √4^2+(-3)^2

d= √16+9

d=√25

d=5

8 0

3 years ago

If f(x) = 3x-1 and g(x)= x+2 find (f-g)(x)

wariber [46]

Answer:

2x-3

Step-by-step explanation:

f(x) = 3x-1

g(x) = x+2

Find (f-g)(x), this means we need to subtract g from x.

(3x-1) - (x+2)

Subtract the like terms:

3x -x = 2x

-1 -2 = -3

Combine them to get 2x-3

7 0

3 years ago