Question

a nut mixture of peanuts and macadamia nuts at a small fair is $1.00 per pound of peanuts and $3.26 per pound of macadamia nuts. over the entire day, 131 pounds of the nut mixture were sold for $248.52. If p is the number peanuts and n is the number of macadamia nuts, then the system of equations that model this scenario is

Answer 1

This answer seems really hard but just don't overthink it. You pretty much don't have to do any math. It took me forever to do this because I was thinking so hard but i re-read it and the answer was right infront of me.

1.00p + 3.26n = $248.52

Answer 2

Answer:

• n + p = 131
• 3.26n + 1.00p = 248.52

Step-by-step explanation:

A system of equations refers to having more than one equations to solve more than one variable with.

The first equation is just using the weight of the nuts. Knowing that a total of 131 pounds of nuts were sold, and that the total weight is the sum of the weight of macadamias(n) and peanuts(p):

n + p = 131

The second equation is using the price of the nuts. Knowing that a total $248.52 was made, and that the total is the sum of the money made from macadamias and peanuts:

3.26n + 1.00p = 248.52