In order to find the equation of a line, you would have to use the equation y=mx+b.
First, find the slope:
There is (1,8) and (2, 16) so plug that in 16-8/2-1 = 8. That's your slope! (Or the m)
Next in order to find b, you have to plug in a point:
y=8x+b
Take (1,8) and plug it in for x and y:
8=8(1)+b
b=0
Your y intercept is 0 (which you can also see on the graph)
So your answer is: y=8x
Answer:
no
Step-by-step explanation:
yes
<u>Answer-</u>
<em>The correct answer is</em>
<em>∠BDC and ∠AED are right angles</em>
<u>Solution-</u>
In the ΔCEA and ΔCDB,
As this common to both of the triangle.
If ∠BDC and ∠AED are right angles, then 
Now as
∠BCD = ∠ACE and ∠BDC = ∠AED,
∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)
Then, ΔCEA ≈ ΔCDB
Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.
slope-point form:
we need the slope (m) and a point.
y-y₀=m(x-x₀)
Given two point A(x₁,y₂) and B(x₂,y₂), the slope of the line is :
m=(y₂-y₁) /(x₂-x₁)
Example 3:
we can take two points:
A(12,2)
B(13,7)
m=(7-2) / (13-12)=5/1=5
therefore:
y-2=5(x-12)
y-2=5x-60
y=5x-60+2
y=5x-58
answer: y=5x-58
Example 4:
we can take two points.
A(0,0)
B(3,1)
m=(1-0)/(3-0)=1/3
Therefore:
y-0=1/3(x-0)
y=x/3
answer: y=x/3
5x + 2y = 7 . . . (1)
y = x + 1 . . . (2)
Putting (2) into (1) gives
5x + 2(x + 1) = 7 => 5x + 2x + 2 = 7 => 7x = 7 - 2 = 5 => x = 5/7
From (2) y = 5/7 + 1 = 12/7
Therefore, solution is {(5/7, 12/7)}
