Answer:
x= -3 and y = 6
Step-by-step explanation:
so basically what you are trying to do is reduce into finding x and y
what you do is you want to find a number to multiply one of the equations in order to get the same x or y value does not matter which
so,...
we can do
either 20x or 15y
we will go with the smallest 15y
so for both equations multiply the whole thing by 5 for the first equation and by 3 for the second
5 x 5x+3y=3 --> 1
3 x 4x+5y=18 --> 2
we then get
25x+15y = 15 -->1
12x + 15y = 54 -->2
then now that you have the same Y values you can subtract ! which cancels out both the 15y
25x+15y = 15 -->1
- 12x + 15y = 54 -->2
13x =-39
so now x=-3 and all you have to do with x = -3 is sub this into either one of the equations that you started with !
x = -3
5(-3) +3y =3
-15 + 3y = 3
3y = 3+15
3y=18
y = 6!
P = 2(L) +2(W)
P = 2(4x+3) + 2(2x)
answer
B. 2(4x+3) + 2(2x)
Answer:
7 Hours 12 Minutes
Step-by-step explanation:
So they one of the printer increases at a rate of 1/12 and the other increases at a rate of 1/18. Since you don't know the time it actually takes, you will replace both numerators with and x. (x/12 and x/18). You want to set these up so that they are adding. (x/12 + x/18=1). Since you're adding, you want to change it to the same denominator. The lowest is 36 so you multiply x/12 by 3/3 (so you don't unbalance the equation) and x/18 by 2/2. You'll end up with 3x/36 + 2x/36= 1 which will simplify to 5x/36=1. Multiply each side by 36 to leave the variable by itself. It becomes 5x=36 and when you divide it by 5 you get 7.2. So it's seven and .2 hours, which is equivalent to7 and 1/5 of an hour or 7 hours and 12 minutes.
Answer:
Step-by-step explanation:
Assuming there is a punitive removal of one point for an incorrect response.
Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60
Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50
I'll use 0.33 as an approzimation for 1/3
Three undiscernable choices: 33% chance of guessing correctly -- Expectation: 0.33*(1) + 0.67*(-1) = -0.33 <== The approximation is a little ugly.
Two undiscernable choices: 50% chance of guessing correctly -- Expectation: 0.50*(1) + 0.50*(-1) = 0.00
And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.
One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00
Answer:
Step-by-step explanation:
Multiply the equation by 4
5x - 2 + 2 = 2*(3y + 2)
5x +0 = 2*3y + 2*2
5x = 6y + 4
5x - 6y = 4 --------------------(I)
Multiply the equation by 6
2*(7y + 3) = 3x + 2*7
14y + 6 = 3x + 14
14y = 3x + 14 - 6
14y = 3x + 8
-3x + 14y = 8 ------------------------(II)
Multiply equation (I) by 3 and equation (II) by 5 and then add
(I)*3 15x - 18y = 12
(II)*5 <u>-15x + 70y = 40</u> {Now add}
52y = 52
y = 52/52
y = 1
Substitute y =1 in equation (I)
5x - 6*1 = 4
5x - 6 = 4
5x = 4 +6
5x = 10
x = 10/5
x = 2
