Jaskson kitten weghed 2 pound

Which of the following is the correct classification of ∆mnp if m<m=35° and m<p=47°?

AnnZ [28]

Answer:

D. Obtuse.

Step-by-step explanation:

We are told that in $\Delta MNP$ $m\angle M=35^o$ and $m\angle P=47^o$ . We are asked to classify our given $\Delta MNP$ .

We can see that angle M and angle P are acute angles as their measure is less than 90 degrees.

Let us find the measure of angle P using angle sum property of triangles, which states that sum of interior angles of a triangle is 180 degrees.

So we can set an equation as:

$m\angle M+m\angle P+m\angle N=180^o$

Upon substituting our given values we will get,

$35^o+47^o+m\angle N=180^o$

$82^o+m\angle N=180^o$

$82^o-82^o+m\angle N=180^o-82^o$

$m\angle N=98^o$

As measure of angle N is 98 degrees, so angle N is an obtuse angle.

Since a triangle having an angle that measures more than 90 degrees is called an obtuse triangle, therefore, $\Delta MNP$ is an obtuse triangle and option D is the correct choice.

4 0

3 years ago

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Alicia, Malik, Joey, and Hailey had some pencils. Alicia gave 18 pencils to Malik. She received 10 pencils from Joey and 23 penc

strojnjashka [21]

Answer:

61

Step-by-step explanation:

subtract the ones she got add the ones she gave away

6 0

2 years ago

Read 2 more answers

PLS ANSWER. The questions is attached. Dont' put like I dont' know the answer if u don't know don't answer pls.

jekas [21]

Answer:

x = 2.4

Step-by-step explanation:

see image for explanation.

Hope it helps

8 0

1 year ago

adidas is ready to launch its new shoe line, but needs to determine what color the shoes should be so that customers will actual

Dmitry [639]

Answer:

Yellow and purple

Step-by-step explanation:

7 0

3 years ago

Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time t > 0 is $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

$\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t$

where, $\text{R}_i_n$ = concentration of salt in the inflow $\times$ input rate of brine solution

and $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

So, $\text{R}_i_n$ = 4 lb/gal $\times$ 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

= 3 gal/min - 2 gal/min

= 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

= $\frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min}$ = $\frac{2A(t)}{500+t} \text{ lb/min }$

Now, the differential equation for the amount of salt A(t) in the tank at a time t > 0 is given by;

= $\frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }$

or $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

4 0

3 years ago