Answer:
m<SQP=124°
Step-by-step explanation:
Hi there!
We're given ΔQRS, the measure of <R (90°), and the measure of <S (34°)
we need to find m<SQP (given as x+72°)
exterior angle theorem is a theorem that states that an exterior angle (an angle on the OUTSIDE of a shape) is equal to the sum of the two remote interior angles (the angle OUTSIDE of a shape will be equal to the sum of 2 angles that are OPPOSITE to that angle).
that means that m<SQP=m<R+m<S (Exterior angle theorem)
substitute the known values into the equation
x+72°=90°+34° (substitution)
combine like terms on both sides
x+72°=124° (algebra)
subtract 72 from both sides
x=52° (algebra)
however, that's just the value of x. Because m<SQP is x+72°, add 52 and 72 together to get the value of m<SQP
m<SQP=x+72°=52°+72°=124° (substitution, algebra)
Hope this helps!
Answer:
37.68
Step-by-step explanation:
C(circumference)= 2pi r
If the diameter is 12, the r adius is 6
plug into equation
2(pi)(6)
=12pi
=37.68
Answer:
Moderate
Step-by-step explanation:
I think sorry if its wrong
Answer:
D. 1
Step-by-step explanation:
7,491 times 19 yields 142, 329
Answer:
1759.52cm^3
Step-by-step explanation:
Given data
Cylinder E
h = 30 cm and
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*30
V= 3.142*16*30
V=1508.16 cm^3
Cylinder F
h=5 cm
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*5
V= 3.142*16*5
V=251.36 cm^3
Hence the total volume is
=251.36+1508.16
= 1759.52cm^3
