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wel
2 years ago
10

The science department buys the equipment shown in the table they bought all three items this year and how many years will they

have had by all three items again

Mathematics
1 answer:
jasenka [17]2 years ago
3 0
Item                          Time bought
MIcroscopes             Every 5 years
Safety goggles          Every 4 years
Test Tube                  Every 2 years

It would take 20 years for them to buy these three items at the same time.

We simply need to find the LCM or least common multiple of the 3 items using the number of years.

Microscopes - 5 years → 5, 10, 15, 20
Goggles - 4 years → 4, 8, 12, 16, 20
Test tubes - 2 years → 2, 4, 6, 8, 10, 12, 14, 16, 18, 20 
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Answer:

The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A study suggested that children between the ages of 6 and 11 in the US have an average weightof 74 lbs, with a standard deviation of 2.7 lbs.

This means that \mu = 74, \sigma = 2.7

What proportion of childrenin this age range between 70 lbs and 85 lbs.

This is the pvalue of Z when X = 85 subtracted by the pvalue of Z when X = 70. So

X = 85

Z = \frac{X - \mu}{\sigma}

Z = \frac{85 - 74}{2.7}

Z = 4.07

Z = 4.07 has a pvalue of 1

X = 70

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 74}{2.7}

Z = -1.48

Z = -1.48 has a pvalue of 0.0694

1 - 0.0694 = 0.9306

The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

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