3 years ago

How many distinct triangles can be formed for which m∠A = 75°, a = 2, and b = 3?

1 answer:

8 0

We can use the Sine Law:a / sin A = b / sin B2 / sin 75° = 3 / sin B2 / 0.966 = 3 / sin B ( after that we will cross multiply )
2 sin B = 3 · 0.9662 sin B = 2.898sin B = 2.898 : 2sin B = 1.499 > 1 ( it is not possible )Answer: A ) No triangles can be formed.

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