25^3/2 = (5^2)^3/2 = 5^(2*(3/2)) = 5^3 = 125
hope this will help you
the range that would be the most appropriate to represent the numerical data on the vertical axis is B. 20 to 100.
<h3>what range would be most appropriate?</h3>
the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.
this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.
find out more on bar graph ranges at brainly.com/question/25196929.
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We conclude that the distance between points C and D is 5 units.
<h3>
How to find the distance between the two points?</h3>
Remember that if we have two points (x₁, y₁) and (x₂, y₂), the distance between these points is:
d = √( (x₂ - x₁)^2 + (y₂ - y₁)^2)
In this case, we know that:
Point C has the coordinates (-1, 4)
Point D has the coordinates (2, 0)
Then the distance between these two points is:
d = √( (-1 - 2)^2 + (0 - 4)^2) = √25 = 5
We conclude that the distance between points C and D is 5 units.
If you want to learn more about distance between points:
brainly.com/question/7243416
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Answer:
x = 6 m
Step-by-step explanation:
The area (A) of a trapezium is calculated as
A = 
h (a + b)
where h is the perpendicular height and a, b the parallel bases
Here A = 60, h = 8, a = 9 and b = x , thus
× 8 × (9 + x) = 60, that is
4(9 + x) = 60 ( divide both sides by 4 )
9 + x = 15 ( subtract 9 from both sides )
x = 6 m
