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abruzzese [7]
3 years ago
8

What shortcut could you use to prove the triangles congruent?

Mathematics
1 answer:
Setler [38]3 years ago
5 0

Answer:

AAS

Step-by-step explanation:

You can see that two angles and one side are congruent.

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-12 -24 which one is greater or less than​
Simora [160]

Answer:

-12 > -24

Step-by-step explanation:

When the numbers are negative the number that is closer to zero is the greatest

7 0
3 years ago
Read 2 more answers
Find the exact value of the expression.<br> tan( sin−1 (2/3)− cos−1(1/7))
Sonja [21]

Answer:

\tan(a-b)=\frac{2\sqrt{5}-20\sqrt{3}}{5+8\sqrt{15}}

Step-by-step explanation:

I'm going to use the following identity to help with the difference inside the tangent function there:

\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}

Let a=\sin^{-1}(\frac{2}{3}).

With some restriction on a this means:

\sin(a)=\frac{2}{3}

We need to find \tan(a).

\sin^2(a)+\cos^2(a)=1 is a Pythagorean Identity I will use to find the cosine value and then I will use that the tangent function is the ratio of sine to cosine.

(\frac{2}{3})^2+\cos^2(a)=1

\frac{4}{9}+\cos^2(a)=1

Subtract 4/9 on both sides:

\cos^2(a)=\frac{5}{9}

Take the square root of both sides:

\cos(a)=\pm \sqrt{\frac{5}{9}}

\cos(a)=\pm \frac{\sqrt{5}}{3}

The cosine value is positive because a is a number between -\frac{\pi}{2} and \frac{\pi}{2} because that is the restriction on sine inverse.

So we have \cos(a)=\frac{\sqrt{5}}{3}.

This means that \tan(a)=\frac{\frac{2}{3}}{\frac{\sqrt{5}}{3}}.

Multiplying numerator and denominator by 3 gives us:

\tan(a)=\frac{2}{\sqrt{5}}

Rationalizing the denominator by multiplying top and bottom by square root of 5 gives us:

\tan(a)=\frac{2\sqrt{5}}{5}

Let's continue on to letting b=\cos^{-1}(\frac{1}{7}).

Let's go ahead and say what the restrictions on b are.

b is a number in between 0 and \pi.

So anyways b=\cos^{-1}(\frac{1}{7}) implies \cos(b)=\frac{1}{7}.

Let's use the Pythagorean Identity again I mentioned from before to find the sine value of b.

\cos^2(b)+\sin^2(b)=1

(\frac{1}{7})^2+\sin^2(b)=1

\frac{1}{49}+\sin^2(b)=1

Subtract 1/49 on both sides:

\sin^2(b)=\frac{48}{49}

Take the square root of both sides:

\sin(b)=\pm \sqrt{\frac{48}{49}

\sin(b)=\pm \frac{\sqrt{48}}{7}

\sin(b)=\pm \frac{\sqrt{16}\sqrt{3}}{7}

\sin(b)=\pm \frac{4\sqrt{3}}{7}

So since b is a number between 0 and \pi, then sine of this value is positive.

This implies:

\sin(b)=\frac{4\sqrt{3}}{7}

So \tan(b)=\frac{\sin(b)}{\cos(b)}=\frac{\frac{4\sqrt{3}}{7}}{\frac{1}{7}}.

Multiplying both top and bottom by 7 gives:

\frac{4\sqrt{3}}{1}= 4\sqrt{3}.

Let's put everything back into the first mentioned identity.

\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}

\tan(a-b)=\frac{\frac{2\sqrt{5}}{5}-4\sqrt{3}}{1+\frac{2\sqrt{5}}{5}\cdot 4\sqrt{3}}

Let's clear the mini-fractions by multiply top and bottom by the least common multiple of the denominators of these mini-fractions. That is, we are multiplying top and bottom by 5:

\tan(a-b)=\frac{2 \sqrt{5}-20\sqrt{3}}{5+2\sqrt{5}\cdot 4\sqrt{3}}

\tan(a-b)=\frac{2\sqrt{5}-20\sqrt{3}}{5+8\sqrt{15}}

4 0
3 years ago
He had to wait 1 hour and 45 minutes at the airport in San Francisco. Then Frank
FinnZ [79.3K]

Answer:

Step-by-step explanation:

4 0
3 years ago
Can someone help me solve this?
Sergio [31]

Answer:

m<c = 104°

m<d = 80°

Step-by-step explanation:

Recall: Opposite angles of a cyclic quadrilateral are supplementary. Therefore, their sum equals 180°. Thus:

m<c + 76° = 180°

m<c + 76° - 76° = 180° - 76° (subtraction property of equality)

m<c = 104°

m<d + 100° = 180°

m<d +100° - 100° = 180° - 100° (subtraction property of equality)

m<d = 80°

8 0
3 years ago
Suppose that a household's monthly water bill (in dollars) is a linear function of the amount of water the household uses (in hu
dolphi86 [110]

Answer:

The monthly cost for 9 HCF is $38.54

Step-by-step explanation:

<em>The graph is missing; however, the question can still be solved</em>

Given

Slope = 1.55

When monthly cost = $47.84, Amount of water = 15 HCF

Required

Determine the monthly cost for 9 HCF

From the question, we understand that it is a linear function;

Linear functions are of the form

y = mx + b

Where y is the function of x and m is the slope

In this case; the function is the monthly water bill

and x is the amount of water

Solving for b

When monthly cost = $47.84, Amount of water = 15 HCF

The function is as follows;

47.84 = 1.55 * 15 + b

47.84 = 23.25 + b

Subtract 23.25 from both sides

47.84 - 23.25= 23.25 - 23.25 + b

24.59 = b

b = 24.59

Solving for the monthly cost for 9 HCF

Here, we have that

x = Amount\ of\ water = 9

m = Slope = 1.55

b = 24.59

Substitute these values in the linear function; y = mx + b

y = 1.55 * 9 + 24.59

y = 13.95 + 24.59

y = 38.54

<em>Hence, the monthly cost for 9 HCF is $38.54</em>

5 0
3 years ago
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