When I graduate, I am going to fine an awesome wife, a girl that loves me and I love her. I want to explore the world and have 1 kid.
~Jurgen
Answer:
You can just keep the points, If she don't like the answers or steps, it's fine, You can keep the points to yourself because you earned them, it's not a big deal
Explanation:
Answer: The answer is: f(x) = 2x^2 + 40x + 200
Explanation:
Given: x is the width of the Artwork
Let W be the Width of the Frame
Let L be the Length of the Frame
Width = x + 10
Length = Width * 2, so by substitution, Length = 2(x + 10)
Area = Width * Length
By substitution:
Area = (x + 10) * 2(x + 10)
f(x) = (x + 10) * (2x + 20)
f(x) = 2x^2 + 20x + 20x + 200
f(x) = 2x^2 + 40x + 200
To test this, if a picture 8" wide is put in this frame, the width would be 8+10 or 18 inches. The length would be twice the width, or 36 inches. The Area is 18 x 36 = 648.
Using the formula:
f(8) = (2 * 8^2) + (40 * 8) + 200
f(8) = (2 * 64) + 320 + 200
f(8) = 128 + 320 + 200
f(8) = 648
Could you please provide an image along with this question to make it a little more clearer?
Thanks
Answer:
1,400
Explanation:
The carrying capacity is the maximum population size of the species that the environment can sustain indefinitely. When the population reaches its carrying capacity, it begins to decrease due to shortages of resources, such as food, water, habitat, and other necessities.
In the given example, we can see the moose population begins to grow when it reaches about 800 individuals. Then, the population keeps growing until it reaches above 1,400 individuals, after which it begins to decrease. Based on that, we can conclude that the carrying capacity of moose in this ecosystem is 1,400.
