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Pavlova-9 [17]
3 years ago
12

During an el Niño event warm surface water moves from the western equatorial Pacific Ocean to the eastern equatorial region. Whi

ch of the following best describes how the warm water w
affect upwelling off the coast of equatorial South America?
The warm surface water will not change upwelling because this region is at the equator and always has warm water
The warm surface water will increase upwelling because of the difference in salinity between the warm surface water and the cold deep water,
The warm surface water will decrease upwelling because the cooler temperatures on land in the region will prevent upwelling.
The warm surface water will decrease upwelling because of the density difference between the warm surface water and the cold deep water.
Advanced Placement (AP)
1 answer:
Westkost [7]3 years ago
3 0

The statement 'warm surface water will decrease upwelling because cooler temperatures on land will prevent upwelling' describes how the warm water affects upwelling. El Niño is a climatic phenomenon.

El Niño is a climate phenomenon characterized by the warming of the surface water in the tropical Pacific Ocean.

The upwelling refers to the rising of deeper and colder water to shallower depths (i.e., the movement of deeper water to shallow levels), which occurs during the El Niño phenomenon.

The El Niño occurs every 2 to 7 calendar years as a consequence of the unusual warming of the sea water surface temperatures in the eastern tropical Pacific Ocean.

Learn more in:

brainly.com/question/1297418

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<h3>What is probability? </h3>

Probability can be defined as the likelihood of an event to occur. In statistics, the mean of the sample distribution typically shows the probability of the population.

From the parameters given:

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The sample proportion \mathbf{\hat p} can be computed by using the expression:

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If the percentage of the probability of all patients in the emergency room = 0.75

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less can be computed as:

\mathbf{( \hat P \leq 0.582) = P \Big( \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}} \leq \dfrac{0.582 - 0.75}{\sqrt{\dfrac{0.75(1-0.75)}{55}}} \Big )}

\mathbf{( \hat P \leq 0.582 )= P \Big( Z \leq \dfrac{-0.168}{\sqrt{0.003409}} \Big )}

\mathbf{( \hat P \leq 0.582) = P \Big( Z \leq -2.88 \Big )}

From the Z distribution table:

\mathbf{( \hat P \leq 0.582) = 0.00198}

\mathbf{( \hat P \leq 0.582) \simeq 0.0020}

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