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frozen [14]
3 years ago
14

Celine has a bottle that contains 20% of milk and the rest water. The bottle has 1 liter of water. Part A: Write an equation in

one variable that can be used to find the total number of liters of milk and water in the bottle. Define the variable used in the equation. (5 points) Part B: How many liters of milk are present in the bottle? Show your work. (5 points)
Mathematics
2 answers:
Alexxx [7]3 years ago
7 0
Percentage of milk PM
Liters of milk LM
Liters of water W
Total number of liters TL
W/100*PM = LM
W+LM =TL

Proof
1 liter / 100 = 10 milliliters
10 ml * 20 = 200 milliliters
200 ml + 1000 ml = 1200 ml
1.2 liters is the total amount of liters.
love history [14]3 years ago
4 0
A.
a=all
0.20a+1=a
minus 0.20a both sides
1=0.80a
divide both sides by 0.80
1.25=all
all-water=milk
1.25-1=milk=0.25
there is 0.25 liters of milk in the bottle

B. 1.25 liters from previous answer
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Liliana is making a vase with a circular base. She wants the area of the base to be between 135 cm2 and 155 cm2. Which circle co
Umnica [9.8K]

Answer:

(b) Circle C is shown. Line segment A C is a radius with length 7 centimeters.

Step-by-step explanation:

Given

Minimum\ Area = 135cm^2

Maximum\ Area = 155cm^2

\pi = 3.14

Required

Which circle could she use

To do this, we simply calculate the areas of all the given circles

The area of a circle is:

Area = \pi r^2

Where

r = radius

a.\ r = 6cm

The area is calculated as thus:

Area = \pi r^2

Area = 3.14 * (6cm)^2

Area = 3.14 * 36cm^2

Area = 114.04cm^2

b.\ r = 7cm

The area is calculated as thus:

Area = \pi r^2

Area = 3.14 * (7cm)^2

Area = 3.14 * 49cm^2

Area = 153.86cm^2

<em></em>

c.\ r = 8cm

The area is calculated as thus:

Area = \pi r^2

Area = 3.14 * (8cm)^2

Area = 3.14 * 64cm^2

Area = 200.96cm^2

d.\ r = 9cm

The area is calculated as thus:

Area = \pi r^2

Area = 3.14 * (9cm)^2

Area = 3.14 * 81cm^2

Area = 254.34cm^2

<em>From the calculations above; only the circle in option (b) has an area within the required range of 135 to 155cm^2</em>

6 0
3 years ago
Read 2 more answers
Find the value of 8^1/3<br> find the value of 8^2/3<br> find the value of 16^3/4
SashulF [63]

the answer to your question is A.

7 0
2 years ago
How does 2π/4 simplify to π/4?
lana [24]
It doesn't
remember that
(x/g) times (y/z)=(x time y)/(g times z) so
2pi/4=(2 times pi)/(4 times 1) so
2pi/4=2/4 times pi/1=1/2 times pi/1=pi/2
5 0
3 years ago
Pls, help me pls pls pls
rjkz [21]

Answer:

14.4

Step-by-step explanation:

you can do 12*1.2= 14.4

becuase they didnt say equal to or less than 24 and they also didnt say equal to or  greater than 12 hope this helps

8 0
3 years ago
A pumpkin is thrown horizontally off of a building at a speed of 2.5\,\dfrac{\text m}{\text s}2.5 s m ​ 2, point, 5, start fract
4vir4ik [10]

Answer:−47.0

​

​

Step-by-step explanation:Step 1. List horizontal (xxx) and vertical (yyy) variables

xxx-direction yyy-direction

t=\text?t=?t, equals, start text, question mark, end text t=\text?t=?t, equals, start text, question mark, end text

a_x=0a

x

​

=0a, start subscript, x, end subscript, equals, 0 a_y=-9.8\,\dfrac{\text m}{\text s^2}a

y

​

=−9.8

s

2

m

​

a, start subscript, y, end subscript, equals, minus, 9, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction

\Delta x=12\,\text mΔx=12mdelta, x, equals, 12, start text, m, end text \Delta y=\text ?Δy=?delta, y, equals, start text, question mark, end text

v_x=v_{0x}v

x

​

=v

0x

​

v, start subscript, x, end subscript, equals, v, start subscript, 0, x, end subscript v_y=\text ?v

y

​

=?v, start subscript, y, end subscript, equals, start text, question mark, end text

v_{0x}=2.5\,\dfrac{\text m}{\text s}v

0x

​

=2.5

s

m

​

v, start subscript, 0, x, end subscript, equals, 2, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction v_{0y}=0v

0y

​

=0v, start subscript, 0, y, end subscript, equals, 0

Note that there is no horizontal acceleration, and the time is the same for the xxx- and yyy-directions.

Also, the pumpkin has no initial vertical velocity.

Our yyy-direction variable list has too many unknowns to solve for v_yv

y

​

v, start subscript, y, end subscript directly. Since both the yyy and xxx directions have the same time ttt and horizontal acceleration is zero, we can solve for ttt from the xxx-direction motion by using equation:

\Delta x=v_xtΔx=v

x

​

tdelta, x, equals, v, start subscript, x, end subscript, t

Once we know ttt, we can solve for v_yv

y

​

v, start subscript, y, end subscript using the kinematic equation that does not include the unknown variable \Delta yΔydelta, y:

v_y=v_{0y}+a_ytv

y

​

=v

0y

​

+a

y

​

tv, start subscript, y, end subscript, equals, v, start subscript, 0, y, end subscript, plus, a, start subscript, y, end subscript, t

Hint #22 / 4

Step 2. Find ttt from horizontal variables

\begin{aligned}\Delta x&=v_{0x}t \\\\ t&=\dfrac{\Delta x}{v_{0x}} \\\\ &=\dfrac{12\,\text m}{2.5\,\dfrac{\text m}{\text s}} \\\\ &=4.8\,\text s \end{aligned}

Δx

t

​

 

=v

0x

​

t

=

v

0x

​

Δx

​

=

2.5

s

m

​

12m

​

=4.8s

​

Hint #33 / 4

Step 3. Find v_yv

y

​

v, start subscript, y, end subscript using ttt

Using ttt to solve for v_yv

y

​

v, start subscript, y, end subscript gives:

\begin{aligned}v_y&=v_{0y}+a_yt \\\\ &=\cancel{0\,\dfrac{\text m}{\text s}}+\left(-9.8\,\dfrac{\text m}{\text s}\right)(4.8\,\text s) \\\\ &=-47.0\,\dfrac{\text m}{\text s} \end{aligned}

v

y

​

​

 

=v

0y

​

+a

y

​

t

=

0

s

m

​

​

+(−9.8

s

m​

)(4.8s)

=−47.0

s

m

5 0
3 years ago
Read 2 more answers
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