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Sedbober [7]
3 years ago
6

If someone answers these i will give brainlest um anyways i will drop the question right below here. THANK YOU

Mathematics
1 answer:
irga5000 [103]3 years ago
4 0
1). The slope is -1
2). Slope: 3 y-intercept: (0,0)
Hope this helps!
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A piece of fabric costs $5.29 a yard which is estimated cost of 16.3 yards of fabric
Cloud [144]

Answer:

your estimate would be $86.22

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
5>z-3 what does z equal????!!!! Plzzzz halp!!
Roman55 [17]

Solving the inequality 5>z-3 we get z

Step-by-step explanation:

Solving the inequality: 5>z-3

Solving:

5>z-3

Switching sides (converting > then to < than)

z-3

Adding 3 on both sides

z-3+3

So, solving the inequality 5>z-3 we get z

Keywords: Solving inequalities

Learn more about Solving inequalities at:

  • brainly.com/question/1465430
  • brainly.com/question/11788572
  • brainly.com/question/4192226

#learnwithBrainly

8 0
3 years ago
Can someone please help me??
vampirchik [111]

Answer:

Plz take full pick so discussing

3 0
3 years ago
in a survey of 7000 women 4431 say they change their nail polish once a week.Construct a 95% confidence interval for the populat
andreyandreev [35.5K]

Answer:

The 95% confidence interval would be given (0.622;0.644).

We are confident (95%) that the true proportion of people that said that they change their nail polish once a week  is between 0.622 and 0.644

Step-by-step explanation:

Data given and notation  

n=7000 represent the random sample taken    

X=4431 represent the people that said that they change their nail polish once a week

\hat p=\frac{4431}{7000}=0.633 estimated proportion of people that said that they change their nail polish once a week

\alpha=0.05 represent the significance level

Confidence =0.95 or 95%

p= population proportion of people that said that they change their nail polish once a week

Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.633 - 1.96 \sqrt{\frac{0.633(1-0.633)}{7000}}=0.622

0.633 + 1.96 \sqrt{\frac{0.633(1-0.633)}{7000}}=0.644

And the 95% confidence interval would be given (0.622;0.644).

We are confident (95%) that the true proportion of people that said that they change their nail polish once a week  is between 0.622 and 0.644

7 0
3 years ago
How do you make x+2y=6 a linear equation
madreJ [45]
Subtract X
2y=-x+6
Then divide by 2
Y=-1/2x+3
5 0
3 years ago
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