All categories

4 years ago

30 degree triangles.. photo provided

Mathematics

2 answers:

lutik1710 [3]4 years ago

7 0

Lets x = short leg

30 60 90 triangle
Ratio of short leg: long leg: hypo = x : x√3 : 2x
Given long leg = 555 feet = 185√3 * √3
So
short leg = 185√3 ft
long leg = 555 ft
hypo = 370 ft
hypo is the longest's height

short leg: The distance from the man's feet to the base of the monument = 185√3 ft
hypo: The distance from the man's feet to the top of the monument = 370 ft

Answer:
A. The distance from the man's feet to the base of the monument is 185√3 feet
D. The segment representing the monument's height is the longest segment in the triangle

Vsevolod [243]4 years ago

6 0

The answer is going to be the second one

You might be interested in

1.) 3x + 5y = 15 2.) 2x 4y = 2 3.)18x + 12y = 24

DiKsa [7]

1). Answer x= -5/3 y + 5

2.) x=2y+1

3.)x=−2/3y+4/3

4 0

3 years ago

Sin 2x + tan 2x = 4tan/ 1- tan^4 prove that

nalin [4]

$\dfrac{4\tan x}{1-\tan^4x}=\dfrac{4\tan x}{(1-\tan^2x)(1+\tan^2x)}$
$=\dfrac{4\tan x}{(1-(\sec^2x-1)\sec^2x}$
$=\dfrac{4\tan x\cos^2x}{2-\sec^2x}$
$=\dfrac{4\sin x\cos x}{2-\sec^2x}$
$=\dfrac{4\sin x\cos^3x}{2\cos^2x-1}$
$=\dfrac{2\sin2x\cos^2x}{\cos2x}$
$=2\tan2x\cos^2x$
$=2\tan2x\left(\dfrac{1+\cos2x}2\right)$
$=\tan2x(1+\cos2x)$
$=\tan2x+\sin2x$

7 0

3 years ago

6 divided by 7215 and i need help its to hard????

forsale [732]

Answer:

If you mean 6 / 7215 it is 0.00083

but if you meant 7215 / 6 it is 1202.5

Step-by-step explanation:

5 0

2 years ago

What is the measure in radians for the central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm?

Monica [59]

Answer:

Para poder definir los radianes, es necesario introducir el concepto de ángulo central. Un ángulo central es un ángulo cuyo vértice está en el centro de un círculo. En el círculo siguiente, el centro es el punto O, la longitud del radio es r, y es el ángulo central y 30 grados equivale a vil.

Step-by-step explanation:

5 0

3 years ago

The height h (in feet) of an object t seconds after it is dropped can be modeled by the quadratic equation h = -16t2 + h0, where

lawyer [7]

$\bf h=-16t^2+255\implies h=-16t^2+0t+255
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}\\\\
\begin{array}{lcccl}
h=& -16 t^2& +0 t& +255\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
h= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
h=\cfrac{-0\pm\sqrt{0^2-4(-16)(255)}}{2(-16)}\implies h=\cfrac{\pm\sqrt{16320}}{-32}
\\\\\\
h=\cfrac{\pm\sqrt{8^2\cdot 255}}{-32}\implies h=\cfrac{\pm 8\sqrt{255}}{-32}\implies h=\cfrac{\mp \sqrt{255}}{4}
\\\\\\
h\approx \mp 3.992179856$

5 0

3 years ago

Read 2 more answers