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mash [69]
3 years ago
13

Angle a is 40 work out the angle of X on the triangle

Mathematics
1 answer:
fredd [130]3 years ago
4 0
50 degrees if it is a right angled triangle

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A sampling of hemlock trees revealed that 7 out of 190 trees are infected with insects. About how many of the 950 hemlock trees
nignag [31]

Answer:

About 35 trees in a state park are infected with insects

Step-by-step explanation:

we know that

7 out of 190 trees are infected with insects

so

using proportion

Find out about how many of the 950 hemlock trees in a state park are infected with insects

\frac{190}{7}=\frac{950}{x} \\\\x=7(950)/190\\\\x= 35

therefore

About 35 trees in a state park are infected with insects

3 0
3 years ago
Write and solve a proportion to answer the question. 36 is 0.9% of what number w? =0.9100
pickupchik [31]

Answer:

Step-by-step explanation:

The question can be written out like this:

36 = 0.009x

Multiply both sides by 1,000:

9x = 36,000

Divide both sides by 9:

x = 4,000

8 0
4 years ago
Pre algebra Simplify 32 ⋅ 35.
aksik [14]
32x35=1,120
To solve this equation, all you have to do is put the two numbers in a calculator connected by multiplication sign,
3 0
4 years ago
9n+21−3n−24 simplify
Thepotemich [5.8K]
Alright First you combine the like terms. 
9n - 3n = 6n 
21 - 24 = -3 

Rewrite the simplified equation
6n - 3 = 0

Solve for n 
6n = 3 
n = 3/6 
n = 1/2 

Ask if you need more help! :)

6 0
3 years ago
A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H
andrey2020 [161]
Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.3y\\
-----&-----&-------&-------\\
mixture&100&0.15&15
\end{array}
\\\\\\
\begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.3y=15\\
----------\\
0.5x+0.3\left( \boxed{100-x} \right)=15
\end{cases}

solve for "x"

what's "y"? well, y = 100 - x
4 0
3 years ago
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