Answer:
x ≤ -7
Step-by-step explanation:
Symbolically, we have 11 - 3x ≥ 32
and we can solve this for x as follows:
Add 3x to both sides. We get:
11 - 3x + 3x ≥ 32 + 3x
Then 11 ≥ 32 + 3x
Reversing the order, we get 3x + 32 ≤ 11
Subtracting 32 from both sides, we get:
3x ≤ -21
Finally, dividing both sides by 3 yields:
x ≤ -7
Ok so assume that if you have
xy=0 then x and y=0
-1/4(x^2-4x+3)>0
multiply both sides by -4 to clear fraction (-4/-4=1)
flip sign
x^2-4x+3<0
factor
(x-3)(x-1)<0
we know that (+) times (-)=(-) and
(-) times (-)=(+) so we don't want them to be both negative, we want different sign
we cannnot have 3 since it would be (0)(2)<0 which is false
we cannot have 1 either since (-2)(0)<0 is also false
lets see if the solution is in betwen 3 and 1 or outside of 3 and 1
ltry 2
2^3-4(2)+3<0
8-8+3<0
3<0
false
therefor it is outside ie
x>3 and x<1
Answer:
Y= -3x + 11
Step-by-step explanation:
Y= -3x + 11 (-3x is your slope and 11 is your y intercept)
Answer:
im bad but good luck on your math(:
Step-by-step explanation: