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gulaghasi [49]
4 years ago
7

Helppppppppppppppppppppppppppppp

Mathematics
1 answer:
podryga [215]4 years ago
3 0
Okay. So, what we do first is do the distributive property by multiply each number in the parenthesis by 3. When we do that, we get (6x + 12), because 3 * 2x is 6x and 4 * 3 is 12. Now, the numbers written out in long form is 5 + 6x + 12 + 6. 6x is in simplified form, because there is nothing that we can combine it with, but we do need to combine the whole numbers. 5 + 12 is 17, and 17 + 6 is 23. The expression in simplified form is 6x + 23. The answer is B.
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vova2212 [387]
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4 0
3 years ago
10. Sonia paid $ 19.55 for 3.4 pounds of salmon. What is the price per pound of the salmon?​
Novosadov [1.4K]
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7 0
3 years ago
Factor the expression to find the zeros
Leno4ka [110]

Answer:

k = (1 , 4)

Step-by-step explanation:

here's your solution

==> k^2 - 5k + 4. [ is expression ]

==> by using middle term split

==> k^2 - 4k - k + 4

==> taking common from each

==> k(k - 4) - 1 (k - 4)

==> (k - 1) , (k - 4).

==> k - 1 = 0

==> k = 1

==> k - 4 = 0

==> k = 4

hence , k = (1 , 4)

hope it helps

4 0
3 years ago
Please answer the problem in the picture below will mark first correct answer brainliest
Alona [7]

Answer:

6x+2y=8

Step-by-step explanation:

We can multiply both sides of the equation by 3 to get 6x+2y=8.

(Note there is more than one possible answer, you could've multiplied both sides by any number.)

8 0
2 years ago
The first-, second-, and third-year enrollment values for a technical school are shown in the table below.
VARVARA [1.3K]

Answer:

The solution to f(x) = t(x) is x = 2010

Option 3 is true.

Step-by-step explanation:

The first-year , second-year , and third-year enrollment values for a technical school are shown in the table below.

Year (x)      First Year f(x)      Second Year s(x)       Third Year t(x)

 2009              785                        756                           756

 2010               740                        785                           740

 2011                690                        710                            781

 2012               732                        732                            710

 2013                781                        755                            800

Now we will check each option.

Option 1: The solution to f(x) = s(x) is x = 2,009

In year 2009, f(x)=s(x)

But 785≠756

Thus, False

Option 2: The solution to f(x) = s(x) is x = 785

x represents year, but 785 it no year

Thus, False

Option 3: The solution to f(x) = t(x) is x = 2010

In year 2010, f(x)=t(x)=740

But 740=740

Thus, True

Option 4: The solution to f(x) = t(x) is x =740

x represents year, but 740 it no year

Thus, False

8 0
3 years ago
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