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docker41 [41]
3 years ago
10

What is 5-to-4 in a percent??

Mathematics
1 answer:
sdas [7]3 years ago
4 0
5/4 = 1.25 ...multiply by 100 to get ur percent = 125%
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The populations and land areas of four cities in Texas are shown.
Ksju [112]
The ratio for population density is population:area

Using this, we find that choices 1, 4, and 5 are true,

:)
8 0
3 years ago
Read 2 more answers
An arrow is launched upward with a velocity of 192 feet per second from the top of a 95-foot stage. What is the maximum height a
Shalnov [3]

9514 1404 393

Answer:

  671 feet

Step-by-step explanation:

There are a couple of ways to figure this. One is to use a sort of shortcut equation to find the distance traveled (d) by an object when subject to some initial velocity (v) and acceleration (a). Here the acceleration due to gravity is -32 ft/s².

  v² = 2ad

  d = v²/(2a) = (192 ft/s)^2/(2·32 ft/s²) = 576 ft

This height is in addition to the starting height of 95 ft, so the arrow's maximum height is ...

  max height = 95 ft + 576 ft = 671 ft

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Another way to work this problem is to start with the equation for ballistic motion. Filling in the given initial velocity and height, we have ...

  h(t) = -16t^2 +192t +95

The time the arrow reaches the maximum height is the time representing the axis of symmetry of the parabola:

  t = -(192)/(2(-16)) = 6

Then the maximum height is ...

  h(6) = -16·6^2 +192·6 +95 = 671

The maximum height is 671 feet.

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<em>Additional comment</em>

For the standard-form quadratic ...

  y = ax^2 +bx +c

The axis of symmetry is ...

  x = -b/(2a)

6 0
3 years ago
1!+2(2!)+3(3!)+...+n(n!)=(n+1)!-1<br><br><br><br><br>​
anyanavicka [17]

Step-by-step explanation:

OK, let's assume it this way:

<em>Sn=1.1!+2.2!+3.3!+...+n.n!</em><em>=</em><em>(</em><em>2</em><em>‐</em><em>1</em><em>)</em><em>.</em><em>1</em><em>!</em><em>+</em><em>(</em><em>3</em><em>-</em><em>1</em><em>)</em><em>.</em><em>2</em><em>!</em><em>+</em><em>(</em><em>4</em><em>-</em><em>1</em><em>)</em><em>3</em><em>!</em><em>+</em><em>.</em><em>.</em><em>.</em><em>+</em><em>(</em><em>(</em><em>n</em><em>+</em><em>1</em><em>)</em><em>-</em><em>1</em><em>)</em><em>.</em><em>n</em><em>!</em>

Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!<em>=</em><em>(</em><em>2</em><em>.</em><em>1</em><em>!</em><em>-</em><em>1</em><em>!</em><em>)</em><em>+</em><em>(</em><em>3</em><em>.</em><em>2</em><em>!</em><em>-</em><em>2</em><em>!</em><em>)</em><em>+</em><em>(</em><em>4</em><em>.</em><em>3</em><em>!</em><em>-</em><em>3</em><em>!</em><em>)</em><em>+</em><em>.</em><em>.</em><em>.</em><em>+</em><em>(</em><em>(</em><em>n-1</em><em>)</em><em>n</em><em>!</em><em>-</em><em>n</em><em>!</em><em>)</em><em>=</em><em>(</em><em>2</em><em>!</em><em>-</em><em>1</em><em>!</em><em>)</em><em>+</em><em>(</em><em>3</em><em>!</em><em>-</em><em>2</em><em>!</em><em>)</em><em>+</em><em>(</em><em>4</em><em>!</em><em>-</em><em>3</em><em>!</em><em>)</em><em>+</em>

Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!=(2.1!-1!)+(3.2!-2!)+(4.3!-3!)+...+((n-1)n!-n!)=(2!-1!)+(3!-2!)+(4!-3!)+<em>.</em><em>.</em><em>.</em><em>+</em><em>(</em><em>n</em><em>+</em><em>1</em><em>)</em><em>!</em><em>-</em><em>n</em><em>!</em><em>=</em><em>(</em><em>n</em><em>+</em><em>1</em><em>)</em><em>!</em><em>-</em><em>1</em><em>!</em><em>=</em><em>(</em><em>n</em><em>+</em><em>1</em><em>)</em><em>!</em><em>-</em><em>1</em>

and boom problem solved

7 0
1 year ago
What is the surface area of this cylinder (round to the nearest tenth) 6.4 m2 25.1 m2 37.7 m2 62.8 m2
denpristay [2]

Answer: 62.8m^2

Step-by-step explanation:

Surface area of a cylinder = 2\pi r^{2} + 2\pi rh

r = 2m, h = 3m

2\pi (2)^{2} + 2\pi (2)(3)

= 62.83185

8 0
3 years ago
Read 2 more answers
F(x) = 3x, g(x) = 1/3f(x). Find g(0)
schepotkina [342]

Answer:

f(1/3)=3 try that its probably right

4 0
2 years ago
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