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2 years ago

How many variable terms are in the expression 3x3y + 5xz − 4y + x − z + 9?

Mathematics

1 answer:

Dimas [21]2 years ago

8 0

Answer:

Step-by-step explanation:

there are only x y and z used in the expression no matter how many times they multiply.

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72 inches=___ yards please and thank you for your help

I am Lyosha [343]

We know that:

$1yd=36in\text{.}$

Then:

$1in=\frac{1}{36}yd\text{.}$

Therefore:

$72in=72\cdot(\frac{1}{36}yd)\text{.}$

Simplifying the above result we get:

$72\cdot\frac{1}{36}yd=2yd\text{.}$

Answer:

$72\text{inches}=2\text{yards.}$

6 0

1 year ago

K/5.6+ 41.5 = 10.8 The solution is k=

Contact [7]

Answer: The solution is k = -171.92.

4 0

2 years ago

Read 2 more answers

PLEASE HELP 5x-2y=30 What is the y value

Ierofanga [76]

Answer:

y = 5/2x -15

Step-by-step explanation:

5x - 2y = 30

-2y = -5x + 30

y = $\frac{5}{2}$ x -15

7 0

3 years ago

Read 2 more answers

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

Please someone all 3 :)

san4es73 [151]

Answer:

1. Anne = 21 Bobby=35, 450, 70+40+30=140

Step-by-step explanation:

1 21÷3=7
7×5=35

7-2=250
5=250
1=50
2×50+7×50=100+350=450
450

we can see that it's multiplied by 10, so 70+40+30=140

6 0

3 years ago