A friend receives the results of a urine test and finds that dissolved nutrients, such as amino acids and glucose, are present i
1 answer:
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Answer:
Check the c in the explanation
Explanation:
a) RNA has three components - 1) 5 - carbon ribose sugar (2) phosphate group (3) nitrogen base
RNA polymerase is an enzyme involved in transcription where genetic material DNA is transcribed into RNA ( mRNA,rRNA,tRNA).
b) the dependent variable here is what we are looking in the experiment , here it is number of nuceotides per second ,the transcription efficiency of RNA polymerase. And the two controls are important wild type without drug and experimental strain without drug these two tells about baseline of transcription rate of an enzyme. so that one can explain the drug effect on a enzyme.
c) In both wild type and exp strain upon treatment with amanitin the transcription rate decreased in exp strain it is not significant whereas in wild type the effect is much higher compare to exp strain and it is significant. this suggests that the mutation in experimental strain must be on larger subunit of the RNA pol enzyme. that mutation might be showing effect of binding drug to the enzyme and also has a role for its enzyme activity.
and the reduction of transcription rate is 100% efficient in wild type compared with exp strain.
d) a null hypothesis is a general statement in a statistics where there is no measured phenomenon between groups.
the change in the amino acid is an important clue, tells that there is no effect in transcription rate between experiment strain with and without drug . which in turn tells that the mutation is imp for the activity of the Enzyme for its role.
Kindly check the attached image below
Answer:
B) 1 black eyes, green skin, two eyes : 1 black eyes, green skin, one eye : 1 black eyes, white skin, two eyes : 1 orange eyes, green skin, two eyes : 1 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye
Explanation:
Parentals: BbGgCc x bbggcc
The punette square diagram of the cross of these two parents is attached.
B = black eyes, b = orange eyes;
G = green skin, g = white skin;
C = two eyes, c = one eye
Progeny with BbGgCc genotype → black eyes, green skin, two eyes = 8
Progeny with BbGgcc genotype → black eyes, green skin, one eye = 8
Progeny with BbggCc genotype → black eyes, white skin, two eyes = 8
Progeny with bbGgCc genotype → orange eyes, green skin, two eyes = 8
Progeny with Bbggcc genotype → black eyes, white skin, one eye = 8
Progeny with bbGgcc genotype → orange eyes, green skin, one eye = 8
Progeny with bbggCc genotype → orange eyes, white skin, two eyes = 8
Progeny with bbggcc genotype → orange eyes, white skin, one eye = 8
So, if we will see them in the form of ratio then each of the genotype will be in the ratio of 1 i.e. black eyes, green skin, two eyes: black eyes, green skin, one eye: black eyes, white skin, two eyes: orange eyes, green skin, two eyes: black eyes, white skin, one eye: orange eyes, green skin, one eye: orange eyes, white skin, two eyes : orange eyes, white skin, one eye = 1:1:1:1:1:1:1:1.
So, in view of above option B is most appropriate.
Note: In a trihybrid cross, a total of 64 progeny types may be produced.
