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umka21 [38]
4 years ago
9

Can someone help me with reviewing for math fsa 7th grade...... Any topic

Mathematics
1 answer:
Svetach [21]4 years ago
4 0
What topic do you need the most help with?
You might be interested in
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
4 years ago
Solve for k 5/8(3k+1)-1/4(7k+2)=1
lesya [120]

Answer:

<h2>k = 7</h2>

Step-by-step explanation:

\dfrac{5}{8}(3k+1)-\dfrac{1}{4}(7k+2)=1\qquad\text{multiply both sides by 8}\\\\8\!\!\!\!\diagup^1\cdot\dfrac{5}{8\!\!\!\!\diagup_1}(3k+1)-8\!\!\!\!\diagup^2\cdot\dfrac{1}{4\!\!\!\!\diagup_1}(7k+2)=8\cdot1\\\\5(3k+1)-2(7k+2)=8\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(5)(3k)+(5)(1)+(-2)(7k)+(-2)(2)=8\\\\15k+5-14k-4=8\qquad\text{combine like terms}\\\\(15k-14k)+(5-4)=8\\\\k+1=8\qquad\text{subtract 1 from both sides}\\\\k=7

3 0
4 years ago
What is the missing number in 12,24,72,288
Ronch [10]
12*2=24
 24*3=72
 72*4=288
 n*(x+1)
288*(4+1)
288*5=1440
5 0
4 years ago
Write the domain and range as an inequality please!!!<br> 
Nat2105 [25]

Answer:

x > -1

Step-by-step explanation:

Domain is the set of x-values that can be inputted into function f(x).

From the graph we can see that our x-values span from -1 to infinity. Since -1 is open dot, it is not included in the domain:

(-1, ∞) or x > -1

5 0
4 years ago
A submarine sits at -300 meters in relation to sea level. Then it descends 115 meters. What is its new position in
Leokris [45]

Answer:

In this question ;

key word is <em><u>descends</u></em> which means <em><u>going down</u></em>

now the position is -300 which means it's under water and it descends 115 m that means now it's even more under water

position now is -300 -115 = <u>-415m</u>

<u> </u>

3 0
3 years ago
Read 2 more answers
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