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ser-zykov [4K]
2 years ago
15

Determine if the relation is a function. In your handwritten work, explain why or why not.

Mathematics
1 answer:
Anna35 [415]2 years ago
6 0

Answer:

Step-by-step explanation:

Its not a function. The reason its not a function is because it doesnt pass the vertical line test. You could graph these points physically or you could think about it. The domain is the x value, while the range is the allowed y values. So by having the same x value relate to two different y values, just makes no sense. Imagine the function is x+4 and we are given in that graph that when x equals 6, the y equals 9 and 10. That isnt possible because we know the answer is 10, not 9, it cant be both.

Another way you could prove this is by graphing. If you try to take the slope in that interval where 6 coorelates to two y values. The change in y is 1, but the change in x is 0. When you divide 1/0, your calculator blows up. Try it

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Simplify the radical expression (-9√28a^2*1/3√63a)<br><br> show work
Dovator [93]
A ≥ 0

-\not9^3\sqrt{28a^2}*\frac{1}{\not3^1}\sqrt{63a}=\\\\ =-3a\sqrt{4*7}*\sqrt{9*7a}=\\\\=-3a*2\sqrt{7}*3\sqrt{7a}\\\\ =-18a\sqrt7*\sqrt 7*\sqrt a=\\\\=-18a*(\sqrt7)^2*\sqrt a =\\\\ =-18a*7*\sqrt a=\\\\ =-126a\sqrt a
8 0
3 years ago
What is the solution of the equation? w - 2 = -3
Viktor [21]
I think the answer would be c
6 0
3 years ago
2.
victus00 [196]

Answer:

With a vertex (h, k) at (0, 3) and given that  a = -3, then the equation of this parabola in vertex form is as follows:

    y = a(x - h)2 + k

    y = -3(x - 0)2 + 3

    y = -3x2 + 3

Step-by-step explanation:

7 0
3 years ago
Is w^2-9w+81 a trinomial square
Yuri [45]
No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
( \sqrt{a}x+ \sqrt{c})^{2} or ( \sqrt{a}x- \sqrt{c})^{2}
so
if w^2-9w+81 is perfect square, factored form is either
( \sqrt{1}x+ \sqrt{81})^{2} or ( \sqrt{1}x- \sqrt{81})^{2}  aka ( x+9)^{2} or  ( x-9)^{2}
expand them
(x+9)^2=x^2+18x+81, wron middle term

(x-9)^2=x^2-18x+81 wrong

so it is not






8 0
3 years ago
If f(x) = -1, solve for x.
weeeeeb [17]

Answer:

No solution.

Explanation:

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace f(x) with 0 and solve for x.

3 0
3 years ago
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