Answer:
do u know the awnser?
Step-by-step explanation:
The mean (rounded to the nearest tenth if needed) of the following data set is: 30, 29, 40, 51, 39, 33, 24, 60, 40, 35, 58
bekas [8.4K]
Mean is just the average so to calculate the average just add up all the data and divide it by the number of data.
so it's gonna be
(30+29+40+51+39+33+24+60+40+35+58) / 11
= 39.9 (corrected to the nearest tenth)
The interquartile range is 6.
Q3-Q1=IQR
17-11=6
Tyler concludes that 5x² will always have a larger output for the same value of x.
<u>Look at the graph below and the table given</u>
Take a random value: x = 0
Here, 1 > 0, making 2^x > 5x²
Hence, 2^x is greater than 5x² at this point. making Tyler's point not applicable.
Disagree with Tyler's point.
Answer:
IQR = 3
Step-by-step explanation:
Interquartile range, which is abbreviated as IQR, is just the difference between the upper quartile (where the box ends) and the lower quartile (where the box starts). AS it is given in the question that that box starts from 4 and ends at . The interquartile range IQR is simply:
IQR = 7 - 4 = 3
The values of data are usually clustured around some central value. Interquartile range tells us how spread out these middle values. It also tells when some values are too far from the central value. The values which are too far are also termed as outlier values
