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Mnenie [13.5K]
3 years ago
15

Tan^2 0+Tan^2 30+Tan^2 60+Sin^2 0​

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

2.996519411885697

Step-by-step explanation:

\tan(20)  +  \tan(230)  +  \tan(260)  +  \sin(20)  = 2.996519411885697

mark me brainliest

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How do I solve this?
andreev551 [17]

Answer:

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Step-by-step explanation:

I haven't worked with absolute value inequalities in awhile, but let's take a wack at this.

We are given the following inequality:

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This implies two possible cases:

[1] -5 <= 2x -3

Or

[2] 2x - 3 <= 5

So let's solve x for both of these cases:

[1] -5 <= 2x - 3

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[2]  2x - 3 <= 5

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So from these cases, we can say the following is true:

x >= -1  and x <= 4

Thus, we can write this in the form

-1 <= x <= 4

Or in interval notation:

{ x is element of reals | -1 <= x <= 4}

Also written as

x is in the range [-1,4]

Where the closed brackets represent 1 and 4 as possible answers whereas parenthesis would imply they were not.

Cheers.

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KATRIN_1 [288]
Did you provide an picture ?!
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