According to the Pythagorean triple, the side lengths that will form a right triangle are:
A. 11, 13, √290
B. 7, 24, 25
<h3>What is the Pythagorean Triple?</h3>
The Pythagorean triple are three set of sides that can form a right triangle if the square of the longest side equals the sum of the squares of the other two smaller sides.
11² + 13² = (√290)²
290 = 290 [correct]
7² + 24² = 25²
625 = 625 [correct]
2² + 5² = 7²
29 ≠ 49 [correct]
Therefore, the side lengths that will form a right triangle are:
A. 11, 13, √290
B. 7, 24, 25
Learn more about the Pythagorean triple on:
brainly.com/question/11994763
#SPJ1
<h2>Question: 252+5+52 Answer: 309</h2><h3>___________________________________</h3><h3>Simplify the expression</h3>
Hope this helps!
Also can I please have Brainliest?
0.9(P - 15) + 0.05P[0.9(P - 15)] + 0.05P
0.9(P - 15)(1 + 0.05P) + 0.05P
From this, we can see that there is a 10% discount indicated by multiplication by 0.9 and a flat discount of $15 from (P - 15)
However, the last term indicates that the delivery cost is 5% that of the original price.
Answer:
your answer will be C. rotation
Step-by-step explanation:
hope it helps...
have a great day!
Answer:
Therefore 6th year his income was $19,700.
Step-by-step explanation:
Given, Joe's annual income has been increasing in some dollar amount . The first year his income was $15,200 and 4th year his income was $17,900.
A=$17900, P= $15,200 and n = 3 year
![A= P(1+\frac{r}{100} )^n](https://tex.z-dn.net/?f=A%3D%20P%281%2B%5Cfrac%7Br%7D%7B100%7D%20%29%5En)
![\Leftrightarrow 17900=15200(1+\frac{r}{100})^3](https://tex.z-dn.net/?f=%5CLeftrightarrow%2017900%3D15200%281%2B%5Cfrac%7Br%7D%7B100%7D%29%5E3)
![\Leftrightarrow (1+\frac{r}{100})^3=\frac{17900}{15200}](https://tex.z-dn.net/?f=%5CLeftrightarrow%20%281%2B%5Cfrac%7Br%7D%7B100%7D%29%5E3%3D%5Cfrac%7B17900%7D%7B15200%7D)
![\Leftrightarrow (1+\frac{r}{100})=(\frac{17900}{15200})^{\frac{1}{3} }](https://tex.z-dn.net/?f=%5CLeftrightarrow%20%281%2B%5Cfrac%7Br%7D%7B100%7D%29%3D%28%5Cfrac%7B17900%7D%7B15200%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D)
![\Leftrightarrow \frac{r}{100}=(\frac{17900}{15200})^{\frac{1}{3} }-1](https://tex.z-dn.net/?f=%5CLeftrightarrow%20%5Cfrac%7Br%7D%7B100%7D%3D%28%5Cfrac%7B17900%7D%7B15200%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D-1)
![\Leftrightarrow r=5.60](https://tex.z-dn.net/?f=%5CLeftrightarrow%20r%3D5.60)
Let
year Joe's income was $19,700.
![\therefore 19700=15,200(1+\frac{5.60}{100} )^{t-1}](https://tex.z-dn.net/?f=%5Ctherefore%2019700%3D15%2C200%281%2B%5Cfrac%7B5.60%7D%7B100%7D%20%29%5E%7Bt-1%7D)
![\Leftrightarrow 1.296= (1+0.056)^{t-1}](https://tex.z-dn.net/?f=%5CLeftrightarrow%201.296%3D%20%281%2B0.056%29%5E%7Bt-1%7D)
![\Leftrightarrow 1.296= (1.056)^{t-1}](https://tex.z-dn.net/?f=%5CLeftrightarrow%201.296%3D%20%281.056%29%5E%7Bt-1%7D)
![\Leftrightarrow log(1.296)= (t-1)log(1.056)](https://tex.z-dn.net/?f=%5CLeftrightarrow%20%20log%281.296%29%3D%20%28t-1%29log%281.056%29)
![\Leftrightarrow \frac{log(1.296)}{log(1.056)}= (t-1)](https://tex.z-dn.net/?f=%5CLeftrightarrow%20%20%5Cfrac%7Blog%281.296%29%7D%7Blog%281.056%29%7D%3D%20%28t-1%29)
![\Leftrightarrow t-1= 4.75](https://tex.z-dn.net/?f=%5CLeftrightarrow%20t-1%3D%204.75)
![\Leftrightarrow t= 4.75+1](https://tex.z-dn.net/?f=%5CLeftrightarrow%20t%3D%204.75%2B1)
≈6
Therefore 6th year his income was $19,700.