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svp [43]
2 years ago
12

Consider the possible solution to each inequality. Choose Yes or No for each question.

Mathematics
1 answer:
ZanzabumX [31]2 years ago
3 0

Answer:

a. No

b. Yes

c. No

d. Yes

e. Yes

Step-by-step explanation:

a. 8 + 13 = 21. No

b. -6 - 10 = -4. Yes

c. 6 × 4.6 = 27.6. No

d. 15 × 3.9 = 58.5. Yes

e. -6 × (-5) = 30. Yes

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Write 7:30 in two ways
Aloiza [94]
Three ways are: 

<u>In Fraction Form:</u>  \frac{7}{30}  
<u>In Ratio its</u>: What you said  7:30

And

In a Percent Form Its:  0.23- %
(I got that from dividing 7 by 30.)

Hope IT helped You. :D
6 0
3 years ago
Read 2 more answers
What is 4/5 * 7/9. Ik It’s easy but I don’t feel like doing it ;)
valina [46]

Answer:

28/45

Step-by-step explanation:

Dont worry i also don't feel like doing fractions most the time they can get very annoying when you have to work with a lot of them.

7 0
2 years ago
Read 2 more answers
The population of a certain country is approximated by the following equation, where x is the number of years since 1980 and P i
marissa [1.9K]

Answer:

In 2010 the population become 206,123,000.

Step-by-step explanation:

Consider the provided equation.

P=2.748x + 126.199

Where P represents the population in millions.

We need to determine the year in which the country had population of 206,123,000.

As P is in millions so divide 206,123,000 by one million.

\frac{206,123,000 }{1,000,000}= 206.123

Substitute P = 206.123 in above equation.

206.123=2.748x + 126.199

79.924=2.748x

x=\frac{79.924}{2.748}

x=29.08

30 year from 1980 the population become 206,123,000.

In 2010 the population become 206,123,000.

6 0
2 years ago
Find one solution for the equation. Assume that all angles involved are acute angles. tangent (3 Upper B minus 32 degrees )equal
raketka [301]

Answer:

Step-by-step explanation:

Equation given

tan(3B-32 ) = cot ( 5B +10 ) = tan [ 90 - ( 5B + 10 ) ]

tan(3B-32 ) = tan  (90 - 5B - 10 )

(3B-32 ) =  (90 - 5B - 10 )

8B = 32 + 80

B = 14° .

5 0
2 years ago
Sketch the region that is common to the graphs of x ≥ 2,
Oliga [24]

a. Find the graph of their common region in the attachment

b. The area of the common region of the graphs is 8 units²

<h3>a. How to sketch the region common to the graphs?</h3>

Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.

  • The graph of x ≥ 2 is the region right of the line x = 2.
  • The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
  • To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.

So, the graph of x + y ≤ 6 is the region below the line y = - x + 6

From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)

Find the graph of their common region in the attachment

<h3>b. The area of the common region</h3>

From the graph, we see that the common region is a right angled triangle with

  • height = 4 units and
  • base = 4 units

So, its area = 1/2 × height × base

= 1/2 × 4 units × 4 units

= 1/2 × 16 units²

= 8 units²

So, the area of the common region of the graphs is 8 units²

Learn more about region common to graphs here:

brainly.com/question/27932405

#SPJ1

6 0
1 year ago
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