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Varvara68 [4.7K]
3 years ago
8

During a recent drought, a water utility in a certain town sampled 100 residential water bills and found that 80 of the residenc

es had reduced their water consumption over that of the previous year. Find a 98% upper confidence bound for the proportion of residences that reduced their water consumption. Round the answer to three decimal places.
Mathematics
1 answer:
Anastasy [175]3 years ago
4 0

Answer: 0.893

Step-by-step explanation:

Given : Sample size of residential water bills: n=100

Number of residences had reduced their water consumption over that of the previous year = 80

Then sample proportion: \hat{p}=\dfrac{80}{100}=0.8

Critical value for 98% confidence= z_{\alpha/2}=2.326

The upper bound for confidence interval for population proportion :

\hat{p}+ z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

=0.8+ (2.326)\sqrt{\dfrac{0.8(1-0.8)}{100}}\\\\=0.8+0.09304=0.89304\approx0.893

Hence, the 98% upper confidence bound for the proportion of residences that reduced their water consumption.=0.893

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