All categories

3 years ago

Evaluate: Find 2x + 3y when x=3 and y=-2

Mathematics

2 answers:

Troyanec [42]3 years ago

7 0

$2x+3y=\\2(3)+3(-2)=\\6-6=\\0$

0

kupik [55]3 years ago

4 0

Plug x=3 and y=-2 in 2x+ 3y, we have:
2*3+ 3*(-2)
= 6 -6
= 0

The final answer is 0~

You might be interested in

Find the area of a circle with a circumference of 12.56 units

vagabundo [1.1K]

Answer:

a = 157.7536pi

Step-by-step explanation:

area = pi*circumference²

a = pi*12.56² = 157.7536*pi

however, if pi just equals 3.14:

probably around 495.346304

6 0

3 years ago

Read 2 more answers

Giving brainliest for CORRECT awnser.

choli [55]

Answer:

C. F(x) = x²

Step-by-step explanation:

"Quadratic" means "second degree". The only function with an exponent of 2 is choice C.

5 0

2 years ago

Question 12 (1 point)

Mademuasel [1]

Answer:

B) Variable Expense

Step-by-step explanation:

Because you choose to have a pet.

3 0

2 years ago

What is a 3 dimensional figure with 3 rectangular faces and 2 triangular faces

Margaret [11]

The Answer is Triangular Prism.

8 0

3 years ago

A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th

umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable X is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, p = 0.09.

An item is defective irrespective of the others.

The random variable X follows a Binomial distribution with parameters n = 9 and p = 0.09.

The repair cost of the item is given by:

$C=3X^{2}+X+2$

Compute the expected cost of repair as follows:

$E(C)=E(3X^{2}+X+2)$

$=3E(X^{2})+E(X)+2$

Compute the expected value of X as follows:

$E(X)=np$

$=4\times 0.09\\=0.36$

The expected value of X is 0.36.

Compute the variance of X as follows:

$V(X)=np(1-p)$

$=4\times 0.09\times 0.91\\=0.3276\\$

The variance of X is 0.3276.

The variance can also be computed using the formula:

$V(X)=E(Y^{2})-(E(Y))^{2}$

Then the formula of $E(Y^{2})$ is:

$E(Y^{2})=V(X)+(E(Y))^{2}$

Compute the value of $E(Y^{2})$ as follows:

$E(Y^{2})=V(X)+(E(Y))^{2}$

$=0.3276+(0.36)^{2}\\=0.4572$

The expected repair cost is:

$E(C)=3E(X^{2})+E(X)+2$

$=(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73$

Thus, the expected repair cost is $3.73.

4 0

3 years ago