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monitta
2 years ago
11

1/2 is equivalent to 1/2•3/3​

Mathematics
1 answer:
ladessa [460]2 years ago
4 0

Answer:

the answer is going to be no

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Helpppp confused
Sveta_85 [38]

Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.

Let's see if there are anything we missed:

 ∞

 Σ  2^n=1+2+4+8+16+...

n=0

We multiply (2-1) on both sides:

       ∞

(2-1)  Σ  2^n=(2-1)1+2+4+8+16+...

      n=0

And we expand;

 ∞

 Σ  2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)

n=0

But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:

 ∞

 Σ  2^n=-1+2(2^n)

n=0

If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.

Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.

Yep, this shows how weird the infinity sign is.

5 0
2 years ago
Find the image of (–7, –3) reflected across the x-axis. A. (–7, 3) B. (7, –3) C. (7, 3) D. (–7, –3)
Naddika [18.5K]

Answer:

(-7, -3) (Answer A)

Step-by-step explanation:

We start with the point (-7, -3).  The x-coordinate does not change at all if we reflect this point across the x-axis.  Whereas the y-value of (-7, -3) is -3, we end up with +3 after this reflection.  The desired image is (-7, +3)  (Answer A)

8 0
2 years ago
Please help me i’ll give points
Umnica [9.8K]

Answer:

A,B,D

Step-by-step explanation:

8 0
2 years ago
Solve the equation.
Levart [38]

Answer:

x=34

Step-by-step explanation:

6 - ( x-7) ^ 1/3 = 3

Subtract 6 from each side

6-6 - ( x-7) ^ 1/3 = 3-6

- ( x-7) ^ 1/3 = -3

Divide each side by a negative

 ( x-7) ^ 1/3 = 3

Cube each side

 ( x-7) ^ 1/3 ^3 = (3)^3

x-7 = 27

Add 7 to each side

x-7+7 = 27+7

x = 34

Check

6 - ( 34-7) ^ 1/3 = 3

6 - (27^1/3 = 3

6 -3 =3

3=3

Good solution

8 0
3 years ago
The upper-left coordinates on a rectangle are (-6,0)(−6,0)left parenthesis, minus, 6, comma, 0, right parenthesis, and the upper
nikklg [1K]

Answer:

See attachment for rectangle

Step-by-step explanation:

Given

A = (-6,0)

B = (-4,0)

Area = 12

Required

Draw the rectangle

First, we calculate the distance between A and B using distance formula;

AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

So, we have:

AB = \sqrt{(-6 - -4)^2 + (0- 0)^2}

AB = \sqrt{(-2)^2 + (0)^2}

AB = \sqrt{4 + 0}

AB = \sqrt{4}

AB = 2

The above represents the length of the triangle.

Next, calculate the width using:

Length * Width = Area

2* Width = 12

Divide both sides by 2

Width = 6

This implies that, the width of the rectangle is 6 units.

We have:

A = (-6,0)

B = (-4,0)

Since A and B are at the upper left and right, then the ther two points are below.

6 units below each of the above point are:

C = (-6,0-6)\\ => C = (-6,-6)

D = (-4,0-6) => D = (-4,-6)

Hence, the points of the rectangle are:

A = (-6,0)

B = (-4,0)

C = (-6,-6)

D = (-4,-6)

<em>See attachment for rectangle</em>

6 0
3 years ago
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