Answer:
1. sum of term = 465
2. nth term of the AP = 30n - 10
Step-by-step explanation:
1. The sum of all natural number from 1 to 30 can be computed as follows. The first term a = 1 and the common difference d = 1 . Therefore
sum of term = n/2(a + l)
where
a = 1
l = last term = 30
n = number of term
sum of term = 30/2(1 + 30)
sum of term = 15(31)
sum of term = 465
2.The nth term of the sequence can be gotten below. The sequence is 20, 50, 80 ......
The first term which is a is equals to 20. The common difference is 50 - 20 or 80 - 50 = 30. Therefore;
a = 20
d = 30
nth term of an AP = a + (n - 1)d
nth term of an AP = 20 + (n - 1)30
nth term of an AP = 20 + 30n - 30
nth term of the AP = 30n - 10
The nth term formula can be used to find the next term progressively. where n = number of term
The sequence will be 20, 50, 80, 110, 140, 170, 200..............
For the first blank where it asks for the perimeter, the perimeter is all the outside sides of a shape added up. So, 6 + 1 + 2 + 4 + 4 + 5 = 22.
For the second blank, you just multiply the entire perimeter by 5, so, 22 times 5=110.
For the third blank, it is basically the same as the previous question. The answer is 5.
For the fourth blank, it is the same perimeter as the first blank, but instead of centimeters, it is in k. So, 22k.
Hope this helped! :)
First, add 2 to both sides. You should have 3/2x=21. Multiply both sides by 2 which gives you 3x= 42. Divide by 3 and you have x=14
Answer:
Answer is 225.
We have to find the sum of 15 terms of the series
sigma 1 to 15 (2n-1)
This can be split as per summation terms as
sigma 2n - sigma 1
sigma 2n can again be simplified by taking 2 outside
sigma 2n= 2 times sum of natural numbers of 1 to 15
= 2(15)(16)/2= 240
sigma 1= 1+1+...15 times= 15
Hence final answer is
= 2 times sigma n - (n) = 240-15 = 225.
Step-by-step explanation:
The sequence is " Algebraic, common difference = −10 " ⇒ 1st answer
Step-by-step explanation:
Let us revise the algebraic and geometric sequences
- The Algebraic sequence is the sequence that has a common difference between each two consecutive terms, like 2 , 5 , 8 , 11 , 14 , .......... the difference between the 5 and 2 is equal to the difference between 8 and 5, and the difference between 11 and 8 and the difference between 14 and 11
- The geometric sequences is the sequence that has a common ratio between each two consecutive terms, like 3 , -9 , 27 , -81 , ...... the ratio between -9 and 3 as the ratio between 27 and -9 as the ratio between -81 and 27
→ x : 1 : 2 : 3 : 4
→ f(x) : 5 : -5 : -15 : -25
x represents the positions of the terms
f(x) represents the value of each term
∵ 1st = 5 and 2nd = -5
∵ -5 - 5 = -10
∵ 2nd = -5 and 3rd = -15
∵ -15 - (-5) = -15 + 5 = -10
∵ 3rd = -15 and 4th = -25
∵ -25 - (-15) = -25 + 15 = -10
∴ There is a common difference -10 between each two
consecutive terms
∴ The sequence is algebraic with common difference -10
The sequence is " Algebraic, common difference = −10 "
Learn more:
You can learn more about the sequences in brainly.com/question/1522572
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