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Nutka1998 [239]
3 years ago
5

Help pls itS BEEN 2 HOURS LUV U <3

Mathematics
1 answer:
nataly862011 [7]3 years ago
7 0

Step-by-step explanation:

Hey there!

The equation of a circle which passes through any point having centre (h,k) is;

( {x - h)}^{2}  + ( {y - k)}^{2}  =  {r}^{2}

In first blank ( x-_ ) keep "-2". In second blank (y - _ ) keep "4" and in last blank ( _ ) keep "36".

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

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MA_775_DIABLO [31]

Answer:

19

Step-by-step explanation:

12 2/3 divided by 2/3 = 19

4 0
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Alexus [3.1K]

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5436

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AnnZ [28]

Given:

The graph of an exponential function.

To find:

The function in the form of f(x)=ab^x.

Solution:

The general form of an exponential function is

f(x)=ab^x                ...(i)

From the given graph it is clear that the function passes through the points (0,4) and (1,7). It means these points will satisfy the function.

For x=0 and f(x)=4,

4=ab^0

4=a(1)

4=a

For x=1 and f(x)=7,

7=ab^1

Putting a=4, we get

7=4(b)

\dfrac{7}{4}=b

Substitute a=4 and b=\dfrac{7}{4} in (i).

f(x)=4\left(\dfrac{7}{4}\right)^x

Therefore, the required exponential function is f(x)=4\left(\dfrac{7}{4}\right)^x.

8 0
3 years ago
The product of three consecutive natural number is 120 . What is their sum ?
icang [17]
Let x = number 1
Let (x+1) = number 2
Let (x+2) = number 3

<span>x(x+1)(x+2)=120\\ (x^{2} +x)(x+2)=120\\ x^{3}+2 x^{2} + x^{2} +2x-120=0\\ x^{3} +3 x^{2} +2x-120=0\\</span>

4 is a solution
x^{3} +3 x^{2} +2x-120=0\\ 4^{3} +3 (4)^{2} +2(4)-120=0\\ 64+48+8-120=0

The first number is 4, the next two are 5 and 6

4x5x6=120

4+5+6=15
8 0
4 years ago
Read 2 more answers
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