3 years ago

What is the value of the discriminant? 2K2 = 10k - 2

Mathematics

1 answer:

Phoenix [80]3 years ago

7 0

Answer:

Step-by-step explanation:

Given a quadratic equation in standard form, ax² + bx + c = 0 : a ≠ 0

Then the discriminant is Δ = b² - 4ac

2k² = 10k - 2 ( subtract 10k - 2 from both sides )

2k² - 10k + 2 = 0 ← in standard form

with a = 2, b = - 10 and c = 2, thus

b² - 4ac = (- 10)² - (4 × 2 × 2) = 100 - 16 = 84

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