Question

Jayden has some dimes and some quarters. He has at most 25 coins worth at least $4.60 combined. If Jayden has 7 dimes, determine all possible values for the number of quarters that he could have.​

Answer 1

Answer:

Step-by-step explanation:

A dime is worth 10 cents. Converting to dollars, it becomes 10/100 = $0.1

A quarter is worth 25 cents. Converting to dollars, it becomes 25/100 = $0.25

Let x represent the number of dimes that Jayden has.

Let y represent the number of quarters that Jayden has.

Jayden has some dimes and some quarters. He has at most 25 coins. It means that

x + y ≤ 25

The coins worth at least $4.60 combined. It means that

0.1x + 0.25y ≥ 4.6 - - - - - - - - - - 1

If Jayden has 7 dimes, then

7 + y ≤ 25

y ≤ 25 - 7

y ≤ 18

Substituting x = 7 into equation 1, it becomes

0.1 × 7 + 0.25y ≥ 4.6

0.7 + 0.25y ≥ 4.6

0.25y ≥ 4.6 - 0.7

0.25y ≥ 3.9

y ≥ 3.9/0.25

y ≥ 15.6

All possible values for the number of quarters that he could have would be

15.6 ≤ y ≤ 18