All categories

4 years ago

Simplify the expression. 16-4 [3+2 divide (9-7)]

Mathematics

1 answer:

klemol [59]4 years ago

5 0

Answer:

Step-by-step explanation:

16-4 (3+2÷2)

16-4 (3+1)

16-4×4

16-16

0 ans.

You might be interested in

Is throw right ASAP

Alexxx [7]

Answer: No it is not.

Step-by-step explanation:

All linear functions can be written in the form y = mx + b, where m is the slope and b is the y-intercept (slope-intercept form). Alternatively, a linear function can be expressed in the form y – y0 = m(x – x0), where m is the slope and (x0, y0) is a point on the line (point-slope form).

7 0

3 years ago

Read 2 more answers

Write and solve an equation to answer the question. 9 is 12% of what number?

luda_lava [24]

12% = 12/100 = 0,12

0,12 x x = 9
x = 9/0.12
x = 75

9 is 12% of 75

5 0

3 years ago

In your sock drawer you have 4 blue, 5 gray, and 3 black socks. half asleep one morning you grab 2 socks at random and put them

timofeeve [1]

you will have 1/4 or 25% probability to pick a black sock because

4 blue socks + 5 gray socks + 3 black socks = 12 socks. but you need to pick one of the 3 black socks so 3 out of 12 or 3/12. simplify to 1/4

6 0

3 years ago

Let <img src="https://tex.z-dn.net/?f=%5Calpha" id="TexFormula1" title="\alpha" alt="\alpha" align="absmiddle" class="latex-form

Margarita [4]

Answer:

$|\alpha| = 2$

Step-by-step explanation:

Since $\alpha$ and $\beta$ are complex conjugates, let's define them as follows:

$\alpha = a+bi$

$\beta = a-bi$

$\frac{\alpha}{\beta^2}=\frac{a+bi}{a^2-b^2-2abi} =\frac{(a+bi)*(a^2-b^2+2abi)}{(a^2-b^2-2abi)*(a^2-b^2+2abi)} =\frac{a^3-3ab^2+(3a^2b-b^3)i}{a^4+2a^2b^2+b^4}$

Since $\frac{\alpha}{\beta^2}$ is a real number, complex part of above result must be zero.

$3a^2b-b^3=0$

From to hold above equality, $b=0$ or $b^2=3a^2$ .

However, since $|\alpha-\beta|=2\sqrt 3$ , $b\neq 0$

So, $b =\sqrt 3 a$ or $b =-\sqrt 3 a$

And since $\alpha$ and $\beta$ are complex conjugates, taking plus or minus sign as found above will not affect the result, so let's write the last version of $\alpha$ and $\beta$ as follows:

$\alpha = a+\sqrt 3 ai$