The number of days for both Companies to have the same total amount is
6.4 days
<h3>Word Problem leading to Algebraic expression</h3>
Given Data
- Let the total payment be y
- Let the number of days be x
Company A
y = 57x+ 32 -----------------1
Company B
y = 62x + 0-----------------2
Equating 1 and 2 we have
57x+ 32 = 62x+ 0
Solving for x we have
62x-57x = 32
5x = 32
Divide both sides by 5
x = 32/5
x = 6.4 days
Learn more about word problem here:
brainly.com/question/13818690
It’s A trust me I just did it
The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2
=0
=>
=0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
#SPJ1
1 to 2 m tall please forgive meh
Answer:
The probability of getting two of the same color is 61/121 or about 50.41%.
Step-by-step explanation:
The bag is filled with five blue marbles and six red marbles.
And we want to find the probability of getting two of the same color.
If we're getting two of the same color, this means that we are either getting Red - Red or Blue - Blue.
In other words, we can find the independent probability of each case and add the probabilities together*.
The probability of getting a red marble first is:

Since the marble is replaced, the probability of getting another red is: 
The probability of getting a blue marble first is:

And the probability of getting another blue is:

So, the probability of getting two of the same color is:

*Note:
We can only add the probabilities together because the event is mutually exclusive. That is, a red marble is a red marble and a blue marble is a blue marble: a marble cannot be both red and blue simultaneously.