Graph the image of the given triangle under a dilation with a scale factor of 1/3 and center of dilation (0, 0) .
2 answers:
We are given : A scale factor of 1/3 and center of dilation (0, 0).
For the given image, the coordinates of the vertices of the triangle are
(0,9), (0,0) and (-6,0).
We can apply formula for finding new coordinates:
Scale factor * [Vertex coordinates of the given image - Coordinate of Center of dilation] +Coordinate of Center of dilation.
Applying same formula to each coordinates we are given.
(0,9) --> 1/3 [ (0,9) - (0,0) ] + (0,0) ] = 1/3 [ (0,9)] +(0,0) = (0,3).
(0,0) --> 1/3 [ (0,0) - (0,0) ] + (0,0) ] = 1/3 [ (0,0] +(0,0) = (0,0).
(0,9) --> 1/3 [ (-6,0) - (0,0) ] + (0,0) ] = 1/3 [ (-6,0)] +(0,0) = (-2,0).
Now, we can plot those resulting coordinates on the graph and form a triangle.
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