50 hours cause you take 150 divided it by 3
A) -3√288=-3√(144*2)=-3√144<span>√2=-3*12</span><span>√2=-36</span><span>√2
b) </span>5√320=5<span>√(64*5)=</span>5<span>√64</span><span>√5=5*8</span><span>√5=40</span><span>√5</span>
If this is in science terms its a plain if this is in mathematical terms, the answer is the number 0 anything below is negative, anything abouve is pos
<h3>Answer</h3>
First multiply everything by 27
Then approximate the terms with 27 if it's possible (27 and 9) (27 and 27)
So now multiply again
And you have
You're welcome if it's right
Please, for clarity, use " ^ " to denote exponentiation:
Correct format: x^4*y*(4) = y*x^2*(13)
This is an educated guess regarding what you meant to share. Please err on the side of using more parentheses ( ) to show which math operations are to be done first.
Your (x+y)2, better written as (x+y)^2, equals x^2 + 2xy + y^2, when expanded.
The question here is whether you can find this x^2 + 2xy + y^2 in your
"X4y(4) = yx2(13)"
Please lend a hand here. If at all possible obtain an image of the original version of this problem and share it. That's the only way to ensure that your helpers won't have to guess what the problem actually looks like.
