Ask question

Ask question

All categories

Oduvanchick [21]

4 years ago

9

(6.7 x 10 5) – (2.3 x 102) =

2 answers:

Furkat [3]4 years ago

5 0

Answer:

6.7 x 105 = 703.5

2.3 x 102 = 234.6

703.5 - 234.6 = 468.9

Step-by-step explanation:

Bingel [31]4 years ago

4 0

-Answer:-10

Step-by-step explanation:

You might be interested in

0.84 is 10 times as much as....<br><br> Could you please explain why?

Olegator [25]

0.084 is the answer because 0.84 divided by 10 is 0.084

6 0

4 years ago

Please help. Simplify 6^-3/6^-5

melomori [17]

Answer:

36.

Step-by-step explanation:

Please correct me if i'm wrong! :)

7 0

3 years ago

Read 2 more answers

Find f of 1 and f of 4

Dafna1 [17]

You have to check f(1) in each one to see if it's right and for f(4)

4 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

Write a real-word problem that can be modeled by 4*(-7).

Mazyrski [523]

Answer:

Kimberly is hiking a huge canyon. Every very hour, she hikes down the canyon, and gets -7 feet deeper. How many feet deep is she in 4 hours?

Step-by-step explanation:

I hope this is good.

8 0

3 years ago