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Dmitry [639]
3 years ago
11

What is 4(2x-1)= -2(3x+16)

Mathematics
1 answer:
adoni [48]3 years ago
6 0
Divide both sides by -2
-2(2x-1)=3x+16
distribute
-4x+2=3x+16
add 4x to both sides
2=7x+16
minus 16 from both sides
-14=7x
divide both sides by 7
-2=x
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Help help please!!
andrey2020 [161]

Answer:

1). y = -7/5x - 4

2). y = 1/5x - 5

Step-by-step explanation:

In this question, we have to write the slope-intercept form of the given information.

Slope intercept form is: y = mx + b

Our "m" value is our slope and our "b" value is our y-intercept.

With that knowledge, we can plug in our given information to the slope-intercept equation:

1) slope = -7/5, y-intercept = -4

Plug -7/5 to "m" and -4 to "b"

y = -7/5x - 4

2) slope = 1/5, y-intercept = -5

Plug 1/5 to "m" and -5 to "b"

y = 1/5x - 5

6 0
3 years ago
The radius of a semicircle is 3 centimeters. What is the semicircle's diameter?​
Aliun [14]

Answer:

6 cm

Step-by-step explanation:

The diameter is 2x the radius

4 0
3 years ago
Read 2 more answers
the smith family is designing new plans for an in ground pool. mr smith draws a rectangular shape with a length that is 5 feet l
Mnenie [13.5K]
Answer:
area of pool = w(w+5) = w^2 + 5w square feet

Explanation:
The height of the pool is used as its width.
Assume that the width of the pool is w feet.
Now, we are given that the length of the pool is 5 feet longer than its width.
This means that:
length of the pool = w + 5 feet
The area of the rectangle is calculated as follows:
area = length * width
area = (w+5) * (w)
area = w^2 + 5w square feet

Hope this helps :)
4 0
3 years ago
Write the first 6 terms of the arithmetic sequence whose first term is 8 and has a common difference of 2
soldier1979 [14.2K]

Answer: The first 6 terms are = 8, 10, 12,14,16,18

Step-by-step explanation:

The NTH term of an Arithmetic Sequence is given as

an = a1 + (n - 1 ) d

where a1 = First term  given as 8 and

d=  common difference given as 2

Therefore  We have that

the first term

an = a1 + (n - 1 ) d = 8+(1-1) 2

a1= 8

second term=

an = a1 + (n - 1 ) d= a2= 8 + (2-1) 2

= 8+ 2(1) = 10

3rd term

an = a1 + (n - 1 ) d= a3= 8 + (3-1) 2

= 8+ 2(2)= 8 + 4=12

4th term

an = a1 + (n - 1 ) d= a4= 8 + (4-1) 2

= 8+ 2(3)= 8+6=14

5th term

an = a1 + (n - 1 ) d= a5= 8 + (5-1) 2

= 8+ 2(4)=8+ 8=16

6th term

an = a1 + (n - 1 ) d= a6= 8 + (6-1) 2

= 8+ 2(5)=8 +10 =18

6 0
3 years ago
What is another way to write 54?
never [62]

Answer:

None of the above.

5 0
3 years ago
Read 2 more answers
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