The smallest area is:
A2 = (1/4) * (A1)
Substituting:
A2 = (1/4) * (12)
A2 = 3 feet ^ 2
Since both are squares then:
L2 = root (3)
L1 = root (12)
The relationship is:
L2 / L1 = (root (3)) / (root (12))
Rewriting:
L2 / L1 = (root (3)) / (root (3 * 4))
L2 / L1 = (root (3)) / (2raiz (3))
L2 / L1 = 1/2
Answer:
The fraction of the side length of the larger rug with a side length of the smaller one is:
L2 / L1 = 1/2
The answer is 10 as all three triangles are similar you can see that there is a parallelogram so just do 2*5
It is worked exactly the same way your other problem was worked.
brainly.com/question/9128908Atrap = (1/2)*(9+5)*5 = 35
Arect = 5*(9 +5 +5 +6.4) = 127
Atot = 127 +2*35 = 197 . . . . in^2
4(x-1)=-4+4x
4x-4=-4+4x
-4x -4x
-4=-4
Not sure what the problem was asking, but it’s solvable!